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 November 17th, 2010, 06:40 AM #1 Newbie   Joined: Nov 2010 Posts: 1 Thanks: 0 discrete math....i need help 1+2+3+...+(4^2- 1^2- 3) / 2 , the left hand side of this equation is a telescoping sum, namely every time we add a term of the same for part of the new term cancels out part of the existing sum. 1. find the corresponding sum if we add up the first N non-negative integers. this should simplify our formula. 2. adapt this method to find the sum of the squares of the first N -non-negative integers. to obtain the telescoping component, use (m+1)^3 -m^3=3m^2+3m+1 3. this method can be adapted to find the sum of the Kth powers of the first N non-negative integers and the sum of the fourth powers of the first N non-negative integers. 4. find a formula for the sum of the 10th powers of the first N non-negative integers that involves a close form featuring an algebraic combination including N. help would be appreciated, please number the responses!!
 November 17th, 2010, 08:23 AM #2 Global Moderator     Joined: Nov 2006 From: UTC -5 Posts: 16,046 Thanks: 938 Math Focus: Number theory, computational mathematics, combinatorics, FOM, symbolic logic, TCS, algorithms Re: discrete math....i need help

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### method of telescoping in discreet mathematics

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