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November 23rd, 2009, 12:57 AM   #1
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Product of 4 factors

Express as the product of four factors
Is this correct?
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November 23rd, 2009, 04:33 AM   #2
six
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Re: Product of 4 factors

Try to distribute it out first. It's actually not too complicated, I worked it out in my head in just a few seconds.
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November 23rd, 2009, 06:26 AM   #3
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Re: Product of 4 factors

Hello, Tartarus!

Quote:
Express as the product of four factors.

Is this correct?

Obviously, you have only two factors . . .


We have the difference of two squares:

[color=beige]. . [/color]a^3)^2 \,-\, (b^3)^2 \;=\;(a^3\,-\,b^3)(a^3\,+\,b^3)" />


Then we have the difference of two cubes and the sum of two cubes:

[color=beige]. . [/color]

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November 23rd, 2009, 12:47 PM   #4
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Re: Product of 4 factors

Quote:
Originally Posted by soroban
[qsize=120]Hello, Tartarus![/size]

Quote:
Express as the product of four factors.

Is this correct?

Obviously, you have only two factors . . .


We have the difference of two squares:

[color=beige]. . [/color]a^3)^2 \,-\, (b^3)^2 \;=\;(a^3\,-\,b^3)(a^3\,+\,b^3)" />


Then we have the difference of two cubes and the sum of two cubes:

[color=beige]. . [/color]

Thanks
I tried another one:

Express as the product of three factors.




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November 23rd, 2009, 06:35 PM   #5
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Correct. Can you also do ?
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November 24th, 2009, 01:47 PM   #6
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Re:

Quote:
Originally Posted by skipjack
Correct. Can you also do ?
Thanks
Yes, but not correctly. How do I know the amount of factors it should have?


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November 26th, 2009, 11:31 AM   #7
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Would knowing that help you find the factors?
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