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November 23rd, 2009, 12:57 AM  #1 
Member Joined: Oct 2009 Posts: 59 Thanks: 0  Product of 4 factors
Express as the product of four factors Is this correct? 
November 23rd, 2009, 04:33 AM  #2 
Senior Member Joined: Oct 2009 Posts: 105 Thanks: 0  Re: Product of 4 factors
Try to distribute it out first. It's actually not too complicated, I worked it out in my head in just a few seconds.

November 23rd, 2009, 06:26 AM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: Product of 4 factors Hello, Tartarus! Quote:
Obviously, you have only two factors . . . We have the difference of two squares: [color=beige]. . [/color]a^3)^2 \,\, (b^3)^2 \;=\;(a^3\,\,b^3)(a^3\,+\,b^3)" /> Then we have the difference of two cubes and the sum of two cubes: [color=beige]. . [/color]  
November 23rd, 2009, 12:47 PM  #4  
Member Joined: Oct 2009 Posts: 59 Thanks: 0  Re: Product of 4 factors Quote:
I tried another one: Express as the product of three factors.  
November 23rd, 2009, 06:35 PM  #5 
Global Moderator Joined: Dec 2006 Posts: 20,965 Thanks: 2214 
Correct. Can you also do ?

November 24th, 2009, 01:47 PM  #6  
Member Joined: Oct 2009 Posts: 59 Thanks: 0  Re: Quote:
Yes, but not correctly. How do I know the amount of factors it should have?  
November 26th, 2009, 11:31 AM  #7 
Global Moderator Joined: Dec 2006 Posts: 20,965 Thanks: 2214 
Would knowing that help you find the factors?


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