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 November 17th, 2009, 02:29 PM #1 Newbie   Joined: Nov 2009 Posts: 3 Thanks: 0 It is possible to rearrange n = ln(x)/ln(y) in terms of x/y? I have tried to rearrange n = ln(x)/ln(y) in terms of x and y, used all the log and exponential rules that I know and I couldn't get anything. It's an expression that I have been trying to solve since last week so that I could get useful data from some kinetics experiments... Thank you very much for any help/suggestion in advance! November 17th, 2009, 03:39 PM   #2
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Re: It is possible to rearrange n = ln(x)/ln(y) in terms of x/y?

Quote:
 Originally Posted by jazzycafe I have tried to rearrange n = ln(x)/ln(y) in terms of x and y, used all the log and exponential rules that I know and I couldn't get anything. It's an expression that I have been trying to solve since last week so that I could get useful data from some kinetics experiments... Thank you very much for any help/suggestion in advance!
nln(y)=ln(x)
y^n=x November 18th, 2009, 04:30 AM   #3
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Re: It is possible to rearrange n = ln(x)/ln(y) in terms of x/y?

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 Originally Posted by mathman nln(y)=ln(x) y^n=x
Please correct me if I'm wrong - I have gotten that expression before but I still can't get an expression in terms of x/y even with that. November 18th, 2009, 01:38 PM #4 Global Moderator   Joined: Dec 2006 Posts: 21,019 Thanks: 2254 Why would you expect to? Wouldn't you fail also if you started with something simpler, such as y = nx�? What exactly did you mean by "get an expression in terms of x/y"? Would y = (x/y)^(1/(n - 1)) count? November 18th, 2009, 01:40 PM   #5
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Re: It is possible to rearrange n = ln(x)/ln(y) in terms of x/y?

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Originally Posted by jazzycafe
Quote:
 Originally Posted by mathman nln(y)=ln(x) y^n=x
Please correct me if I'm wrong - I have gotten that expression before but I still can't get an expression in terms of x/y even with that.
I am not sure what you are looking for? What do mean exactly by "expression"?

y^(n-1) = x/y November 18th, 2009, 04:20 PM #6 Newbie   Joined: Nov 2009 Posts: 3 Thanks: 0 Re: It is possible to rearrange n = ln(x)/ln(y) in terms of x/y? *Scratch head* Apologies in advance if I wasn't wording it properly - I have always been taught that rearranging an equation in terms of x means that you want x = R.H.S. where R.H.S. does not contain x. So what I meant by rearranging n = ln(x)/ln(y) in terms of x/y is an equation in the form of x/y = f(n)... I think; and that seems beyond me... :\ November 18th, 2009, 05:58 PM #7 Global Moderator   Joined: Dec 2006 Posts: 21,019 Thanks: 2254 That's not the usual meaning, but you already have x/y = y^(n - 1). That equation implies n cannot stay the same when x and y are doubled unless n = 1. Hence an equation of the form x/y = f(n) is possible only if n has the fixed value 1, when 1 = ln(x)/ln(y) reduces to x/y = 1. Tags lnx or lny, rearrange, terms, x or y ,

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