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November 12th, 2009, 04:25 PM   #1
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Math problem

Hi everyone!

Heres another math problem...

Ghuraba
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 November 12th, 2009, 04:41 PM #2 Senior Member   Joined: Oct 2009 Posts: 105 Thanks: 0 Re: Math problem seems to me like you don't even need to worry about the first guy wire at all. You need a function that deals with the Opposite Over Adjacent.
November 12th, 2009, 04:50 PM   #3
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Re: Math problem

Quote:
 Originally Posted by six seems to me like you don't even need to worry about the first guy wire at all. You need a function that deals with the Opposite Over Adjacent.
You mean the tangent ratio?

 November 12th, 2009, 07:49 PM #4 Newbie   Joined: Nov 2009 Posts: 6 Thanks: 0 Re: Math problem I would redraw it using only what I need: We'll say the hypotenuse is x. That is the opposite. The reference angle is 64º. The adjacent line is 18.1m. Tan = Opposite / Adjacent tan64º = x/18.1m 2.05 = x/18.1m 37.11m
 November 22nd, 2009, 12:26 AM #5 Member   Joined: Nov 2009 Posts: 31 Thanks: 0 Re: Math problem Thank you for the help! I just have one "on the side" question ... why does it make sense to multiply 2.05 by 18.1?
 November 22nd, 2009, 01:58 AM #6 Global Moderator   Joined: Dec 2006 Posts: 20,095 Thanks: 1905 Because the right-hand side, x/18.1m, when multipled by 18.1m gives x (by the definition of division), and what's done to the right-hand side needs to be done to the left-hand side also.
November 23rd, 2009, 07:01 PM   #7
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Re: Math problem

Quote:
 Originally Posted by Existence I would redraw it using only what I need: We'll say the hypotenuse is x. That is the opposite.
No. The hypotenuse is across from the right angle. The other leg (besides the 18.1) is x, the side opposite from the reference angle.

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