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October 31st, 2009, 07:56 AM   #1
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Deflection Angle of Closed Traverse: Traverse Theory

How do I calculate the deflection angle at B? The deflection at angle B is basically the line AB extended past B, and the angle created by B,B',C if that makes sense.

[attachment=1:2j71u0mv]Traverse Theory.JPG[/attachment:2j71u0mv]



[attachment=0:2j71u0mv]TT Cleared.JPG[/attachment:2j71u0mv]
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October 31st, 2009, 08:22 AM   #2
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2. Interior angle at B = 4236' + 6456' = 10732'. Since it's an interior angle, not a deflection angle, the left/right question doesn't make sense.

1. Your definition of deflection angle builds in "clockwise" (i.e., "right"), rather than anti-clockwise, whenever the vertices are alphabetically ordered clockwise (at least when the polygon is convex). The deflection angle at B = 180 - 10732' = 7228'.

3. Bearing of CD is S6456'E - 3816' = S2640'E.

4. Can you do this final part? (Check the meaning of "azimuth" if you don't already know it.)
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October 31st, 2009, 11:56 AM   #3
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Re: Deflection Angle of Closed Traverse: Traverse Theory

Ok, so in a clockwise approach:

Az AB= 4236'
+180
Az BA= 22236'
-?B 10732'
Az BC= 11504'
+180
Az CB= 29504'
-?C 14344'
Az CD= 15120'
+180
Az DC= 33120'
-?D 3816'
Az DA= 29304'
-180
Az AD= 11304'

What am I doing wrong?
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October 31st, 2009, 01:19 PM   #4
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What the . . . ? The line is already annotated N7042'W. Just subtract that angle from 360 to get the angle clockwise from due North, i.e., 28918'.
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October 31st, 2009, 01:40 PM   #5
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Re: Deflection Angle of Closed Traverse: Traverse Theory

OH I think I see now, so would this be TRUE of azimuth and bearing relation:

N.E. Quadrant: Bearing = Azimuth

S.E. Quadrant: 180 - Azimuth = Bearing AND 180 - Bearing = Azimuth

S.W. Quadrant: Azimuth - 180 = Bearing AND 180 + Bearing = Azimuth

N.W. Quadrant: 360 - Azimuth = Bearing AND 360 - Bearing = Azimuth


I tried to calculate it by going through the entire process, but should I not have produced the same answer anyway?
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October 31st, 2009, 02:42 PM   #6
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S.W. Quadrant: Azimuth - 180 = Bearing AND 180 + Bearing = Azimuth
is what you probably intended.

Now you should be able to spot the errors you made earlier.
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October 31st, 2009, 02:53 PM   #7
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Re: Deflection Angle of Closed Traverse: Traverse Theory

Will do. Thanks you've been an awesome amount of help.
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