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October 18th, 2009, 07:56 PM  #1 
Newbie Joined: Oct 2009 Posts: 1 Thanks: 0  Help with a probability problem
OK, I can't seem to figure this out logically... any help? 61% of students attend 4year institutions and 39% 2year institutions. 4Year Institutions 2Year Institutions Males: 44% Males: 41% Females: 56% Females: 59% a) Find the four probabilities of each combo of gender and type of institution in a table. Be sure that probabilities sum to 1. Men Women 4Year Institution 0.44 0.56 2Year Institution 0.41 0.59 b) Consider randomly selecting a female student from this population. What is the probability that she attends a 4Year Institution? P (Fouryear and twoyear) = P ( P (Fouryear) 0.56 + 0.59  .44  .41 = (Is this a conditional probability? If not, what is it?) 
October 19th, 2009, 03:48 PM  #2 
Member Joined: Oct 2009 Posts: 52 Thanks: 0  Re: Help with a probability problem
a) the four probabilities of each combo of gender and type of institution P(Male and attends 4 year institution) = 0.61 * 0.44 = 0.2684 P(Female and attends 4 year institution) = 0.61 * 0.56 = 0.3416 P(Male and attends 2 year institution) = 0.39 * 0.41 = 0.1599 P(Female and attends 2 year institution) = 0.39 * 0.59 = 0.2301 You can now put these probabilities into a table. (These probabilities sum to 1) b) Yes. This one s a conditional probability P(attends 4 year institution  female) = P(attends 4 year instition and female) / P(female) = 0.3416 /(0.3416 + 0.2301) = 0.5975 Cheers 

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