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 October 18th, 2009, 06:56 PM #1 Newbie   Joined: Oct 2009 Posts: 1 Thanks: 0 Help with a probability problem OK, I can't seem to figure this out logically... any help? 61% of students attend 4-year institutions and 39% 2-year institutions. 4-Year Institutions 2-Year Institutions Males: 44% Males: 41% Females: 56% Females: 59% a) Find the four probabilities of each combo of gender and type of institution in a table. Be sure that probabilities sum to 1. Men Women 4-Year Institution 0.44 0.56 2-Year Institution 0.41 0.59 b) Consider randomly selecting a female student from this population. What is the probability that she attends a 4-Year Institution? P (Four-year and two-year) = P ( P (Four-year) 0.56 + 0.59 - .44 - .41 = (Is this a conditional probability? If not, what is it?)
 October 19th, 2009, 02:48 PM #2 Member   Joined: Oct 2009 Posts: 52 Thanks: 0 Re: Help with a probability problem a) the four probabilities of each combo of gender and type of institution P(Male and attends 4 year institution) = 0.61 * 0.44 = 0.2684 P(Female and attends 4 year institution) = 0.61 * 0.56 = 0.3416 P(Male and attends 2 year institution) = 0.39 * 0.41 = 0.1599 P(Female and attends 2 year institution) = 0.39 * 0.59 = 0.2301 You can now put these probabilities into a table. (These probabilities sum to 1) b) Yes. This one s a conditional probability P(attends 4 year institution | female) = P(attends 4 year instition and female) / P(female) = 0.3416 /(0.3416 + 0.2301) = 0.5975 Cheers

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