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 October 18th, 2009, 06:56 PM #1 Newbie   Joined: Oct 2009 Posts: 1 Thanks: 0 Help with a probability problem OK, I can't seem to figure this out logically... any help? 61% of students attend 4-year institutions and 39% 2-year institutions. 4-Year Institutions 2-Year Institutions Males: 44% Males: 41% Females: 56% Females: 59% a) Find the four probabilities of each combo of gender and type of institution in a table. Be sure that probabilities sum to 1. Men Women 4-Year Institution 0.44 0.56 2-Year Institution 0.41 0.59 b) Consider randomly selecting a female student from this population. What is the probability that she attends a 4-Year Institution? P (Four-year and two-year) = P ( P (Four-year) 0.56 + 0.59 - .44 - .41 = (Is this a conditional probability? If not, what is it?) October 19th, 2009, 02:48 PM #2 Member   Joined: Oct 2009 Posts: 52 Thanks: 0 Re: Help with a probability problem a) the four probabilities of each combo of gender and type of institution P(Male and attends 4 year institution) = 0.61 * 0.44 = 0.2684 P(Female and attends 4 year institution) = 0.61 * 0.56 = 0.3416 P(Male and attends 2 year institution) = 0.39 * 0.41 = 0.1599 P(Female and attends 2 year institution) = 0.39 * 0.59 = 0.2301 You can now put these probabilities into a table. (These probabilities sum to 1) b) Yes. This one s a conditional probability P(attends 4 year institution | female) = P(attends 4 year instition and female) / P(female) = 0.3416 /(0.3416 + 0.2301) = 0.5975 Cheers Tags probability, problem Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post bsjmath Advanced Statistics 2 March 1st, 2014 02:50 PM ystiang Advanced Statistics 1 February 13th, 2014 04:27 PM halloweengrl23 Advanced Statistics 3 March 23rd, 2012 02:27 AM adiptadatta Probability and Statistics 1 May 11th, 2010 06:46 AM indian Algebra 0 February 21st, 2008 04:10 PM

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