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October 5th, 2009, 01:58 PM  #1 
Newbie Joined: Oct 2009 Posts: 2 Thanks: 0  Combination Questions
1. Solve the equation for n algebraically. nCn2 = 10 Would I have to divide the left side by (n)(n)(n1)(n2), which would cancel out (n) and (n2). Im stuck with what to do after that. Thanks. 
October 5th, 2009, 02:50 PM  #2 
Senior Member Joined: Mar 2007 Posts: 428 Thanks: 0  Re: Combination Questions
1. n!/[2!(n2)!] = n(n1)/2 ... 2. Figure it for case one, being 6 pens and 8 pencils, then for case two, being 7 pens and 7 pencils and compare the two results. 
October 5th, 2009, 03:00 PM  #3  
Newbie Joined: Oct 2009 Posts: 2 Thanks: 0  Re: Combination Questions Quote:
So number 1 would be nCn2 = 10 nCn2/(n)(n1) = 10n(n1)/2??  
October 5th, 2009, 06:12 PM  #4 
Senior Member Joined: Mar 2007 Posts: 428 Thanks: 0  Re: Combination Questions
Try again, using the equality I gave you. I used the fact that nCn2 = n!/2!(n2)!, that is all. Now simplify to what I gave you and sub that into the original equation. If you are doing combinations, you should be past simple algebraic equations and so be able to finish it now.


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