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September 27th, 2009, 02:14 PM  #1 
Newbie Joined: Sep 2009 Posts: 1 Thanks: 0  Transforming Equations
Have a test on tuesday.... We're just doing basic review (first weeks of school)... Anyway I am stuck on a few problems on transforming equations and am wondering if the misc can help Isolate for the given variable: 1. x+y=xy Solve for Y 2. x+y+z=xyz Solve for Z 3. (1/x) + (1/y)=(1/x)(1/y) Solve for Y 4. (1/x) + (1/y) + (1/z)= (1/x)(1/y)(1/z) Solve for Z 
September 28th, 2009, 06:30 AM  #2 
Senior Member Joined: Mar 2009 Posts: 318 Thanks: 0 
How far have you gotten? Where are you stuck on each of these? Please be complete. Thank you! 
September 29th, 2009, 02:07 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,295 Thanks: 1686 
Each equation needs to be rearranged into the form ax = b, where x is the variable you are asked to solve for. The answer will then be x = b/a (provided a is not zero). If there are, say, two terms involving x, the rearranged equation would be of the form (a + c)x = b, and the solution would be x = b/(a + c) (provided a + c is not zero).

September 29th, 2009, 05:34 AM  #4 
Senior Member Joined: Mar 2007 Posts: 428 Thanks: 0  Re: Transforming Equations
Surely, if it is a review, the rules are already evident. If there is absolutely no sign of success, then I'd strongly recommend getting a tutor, as there is usually much that needs to be discussed. These studies, like others, require classroom dialogue as well as text and notes for reference. The solution of some more examples, a very few isolated ones, will not cover the main ideas to enable individual solution at a later date, and it is those main ideas that need to be noted then discussed practiced. Otherwise, showing a little effort would be very much to your advantage. 
September 29th, 2009, 07:16 AM  #5 
Newbie Joined: Sep 2009 Posts: 2 Thanks: 0  Re: Transforming Equations
1. x + y = xy x = xy  y x = y(x  1) y = x / (x1) 

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