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September 20th, 2009, 03:38 PM  #1 
Newbie Joined: Sep 2009 Posts: 1 Thanks: 0  Formula to always get 28
I need to create a formula where the user would start with x and do at least 4 steps (multiplication, division or subtraction... no *0 allowed) to that number and always get 28. For example x = any number x+5 = n 2n+10 = y 2y+ 6 = z final step z+3 = 28 obviously that is nor correct. Thank you! 
September 20th, 2009, 06:25 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,298 Thanks: 1971 
x = any number Subtract the number from itself and then add 1: x  x + 1 = 1 = n Multiply the result by 2 and then add 10: 2n + 10 = 2(1) + 10 = 12 = y Subtract 2 from the result: y  (2) = 12 + 2 = 14 = z Multiply the result by 2: 2z = 2(14) = 28 

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