Algebra Pre-Algebra and Basic Algebra Math Forum

 September 20th, 2009, 03:38 PM #1 Newbie   Joined: Sep 2009 Posts: 1 Thanks: 0 Formula to always get 28 I need to create a formula where the user would start with x and do at least 4 steps (multiplication, division or subtraction... no *0 allowed) to that number and always get 28. For example x = any number x+5 = n 2n+10 = y 2y+ 6 = z final step z+3 = 28 obviously that is nor correct. Thank you! September 20th, 2009, 06:25 PM #2 Global Moderator   Joined: Dec 2006 Posts: 21,128 Thanks: 2336 x = any number Subtract the number from itself and then add 1: x - x + 1 = 1 = n Multiply the result by 2 and then add 10: 2n + 10 = 2(1) + 10 = 12 = y Subtract -2 from the result: y - (-2) = 12 + 2 = 14 = z Multiply the result by 2: 2z = 2(14) = 28 Tags formula Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post NuNu_dagobah Computer Science 4 January 8th, 2013 08:31 AM nsrmsm Number Theory 7 October 15th, 2012 06:36 AM r-soy Physics 3 December 23rd, 2010 09:54 PM agro Probability and Statistics 3 August 27th, 2009 07:17 AM NuNu_dagobah Abstract Algebra 0 December 31st, 1969 04:00 PM

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