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September 16th, 2009, 04:52 PM  #1 
Newbie Joined: Sep 2009 Posts: 9 Thanks: 0  NEED HELP PLEASE :)
300 grams of type A Raisin Bran is mixed with 500 grams of type B Raisin Bran to produce a mixture which is 11% raisins. Type A Raisin Bran has twice as many raisins per kilogram as type B. What percentage of raisins are in each type of raisin bran? I dont know how to figure out the equations. Any help would be great. Thanks 
September 16th, 2009, 08:16 PM  #2 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,930 Thanks: 1124 Math Focus: Elementary mathematics and beyond 
Let x be the percentage of raisins in Type A and let y be the percentage of raisins in Type B. 300(x/100) + 500(y/100) = 800(11/100) ? 3x + 5y = 88 and, since Type A has twice as many raisins as Type B, x  2y = 0. 
September 16th, 2009, 08:22 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,469 Thanks: 2038 
Let type B Raisin Bran have x grams of raisins per kilogram, so in 500 grams of it there are x/2 grams of raisins. Now calculate the raisin content for 300 grams of Type A Raisin Bran, etc.


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