My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum


Reply
 
LinkBack Thread Tools Display Modes
September 16th, 2009, 04:52 PM   #1
Newbie
 
Joined: Sep 2009

Posts: 9
Thanks: 0

NEED HELP PLEASE :)

300 grams of type A Raisin Bran is mixed with 500 grams of type B Raisin Bran to produce a mixture which is 11% raisins. Type A Raisin Bran has twice as many raisins per kilogram as type B. What percentage of raisins are in each type of raisin bran?

I dont know how to figure out the equations. Any help would be great. Thanks
jason7377 is offline  
 
September 16th, 2009, 08:16 PM   #2
Global Moderator
 
greg1313's Avatar
 
Joined: Oct 2008
From: London, Ontario, Canada - The Forest City

Posts: 7,950
Thanks: 1141

Math Focus: Elementary mathematics and beyond
Let x be the percentage of raisins in Type A and let y be the percentage of raisins in Type B.

300(x/100) + 500(y/100) = 800(11/100) ? 3x + 5y = 88 and, since Type A has twice as many raisins as Type B, x - 2y = 0.
greg1313 is offline  
September 16th, 2009, 08:22 PM   #3
Global Moderator
 
Joined: Dec 2006

Posts: 20,835
Thanks: 2162

Let type B Raisin Bran have x grams of raisins per kilogram, so in 500 grams of it there are x/2 grams of raisins. Now calculate the raisin content for 300 grams of Type A Raisin Bran, etc.
skipjack is offline  
Reply

  My Math Forum > High School Math Forum > Algebra



Search tags for this page
Click on a term to search for related topics.
Thread Tools
Display Modes






Copyright © 2019 My Math Forum. All rights reserved.