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August 30th, 2009, 08:35 AM   #1
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stuck on problem

Please help me solve this problem.
I've been working on this problem,and i just keep reducing it to Y=(-3/-2)x-5 and x=(2/3)y+(10/3) and i don't know what to do next.
i haven't gotten to the second part because i am stuck with the first part.
I'd be grateful if someone could help me (problem below).

Solve this system for x and y.


Find the sum of your x and y values. Multiply your answer by the product of your x and y values raised to the fourth power.
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August 30th, 2009, 09:45 AM   #2
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Re: stuck on problem

First multiply both equations by 6.
Then solve for x in the second equation, which will result in an expression in y.
Replace x in the first equation by this expression, and it is easy to solve for y.
After that it is also easy to find x.
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August 30th, 2009, 01:50 PM   #3
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Re: stuck on problem

i still don't get it
i need more help. PLEASE!!!
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August 30th, 2009, 02:39 PM   #4
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You need to be more careful.

From the first equation, x/2 + 1 - (y/3 + 4/3) = 4.
Hence x/2 = y/3 + 4/3 + 4 - 1 = y/3 + 13/3.

From the second equation, x/2 + y/2 = 1/2 + x/3 - y/3.
Hence x/2 - x/3 = 1/2 - y/2 - y/3, and so x/2 = 3/2 - 5y/2.

It follows that y/3 + 13/3 = 3/2 - 5y/2,
and so y/3 + 5y/2 = 3/2 - 13/3,
i.e., 17y = -17,
so y = -1.

Hence x/2 = y/3 + 13/3 = -1/3 + 13/3 = 4,
so x = 8.
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August 30th, 2009, 02:53 PM   #5
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Re: stuck on problem

THANK YOU SOOOOOOO MUCH!!
YOU my friend are a GENIUS!!!!!
I cant thank you guys enough for helping me out
THANKS AGAIN
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August 30th, 2009, 10:14 PM   #6
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Quote:
Originally Posted by adriana.alrb
Find the sum of your x and y values. Multiply your answer by the product of your x and y values raised to the fourth power.
We know that x + y = 8 + (-1) = 7. Is the second sentence mathematically stated as (x + y)(xy)^4, or {xy(x + y)}^4?
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