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June 6th, 2007, 01:33 PM   #1
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Mixture

Steven wants to market a new blend of coffee that will cost 3 dollars and 90 cents per pound by mixing two coffees that sell for 2 dollars and 75 cents and 5 dollars per pound, respectively. What amounts of each coffee should be blended to obtain the desired mixture?

HINT GIVEN:

Assume that the total weight of the desired blend is 100 pounds.
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June 7th, 2007, 06:50 AM   #2
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Let c be the proportion of the cheaper coffee in the blend, then

3.90 = 2.75c + 5.00(1 - c),

so c = (5 - 3.9)/(5 - 2.75) = 1.1/2.25 = 22/45.

Hence a 22:23 mix is required to achieve the mixture described.
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