June 6th, 2007, 02:33 PM  #1 
Senior Member Joined: Dec 2006 From: New Jersey Posts: 378 Thanks: 1  Mixture
Steven wants to market a new blend of coffee that will cost 3 dollars and 90 cents per pound by mixing two coffees that sell for 2 dollars and 75 cents and 5 dollars per pound, respectively. What amounts of each coffee should be blended to obtain the desired mixture? HINT GIVEN: Assume that the total weight of the desired blend is 100 pounds. 
June 7th, 2007, 07:50 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,865 Thanks: 1833 
Let c be the proportion of the cheaper coffee in the blend, then 3.90 = 2.75c + 5.00(1  c), so c = (5  3.9)/(5  2.75) = 1.1/2.25 = 22/45. Hence a 22:23 mix is required to achieve the mixture described. 

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