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 June 6th, 2007, 02:33 PM #1 Senior Member   Joined: Dec 2006 From: New Jersey Posts: 378 Thanks: 1 Mixture Steven wants to market a new blend of coffee that will cost 3 dollars and 90 cents per pound by mixing two coffees that sell for 2 dollars and 75 cents and 5 dollars per pound, respectively. What amounts of each coffee should be blended to obtain the desired mixture? HINT GIVEN: Assume that the total weight of the desired blend is 100 pounds.
 June 7th, 2007, 07:50 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,274 Thanks: 1959 Let c be the proportion of the cheaper coffee in the blend, then 3.90 = 2.75c + 5.00(1 - c), so c = (5 - 3.9)/(5 - 2.75) = 1.1/2.25 = 22/45. Hence a 22:23 mix is required to achieve the mixture described.

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