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May 11th, 2009, 05:26 PM  #1 
Newbie Joined: Apr 2009 Posts: 5 Thanks: 0  Quadratic Formula
Write the equation as a quadratic equation in y and use the quadratic formula to solve for y. x^2y^22x4y4=0 
May 12th, 2009, 06:41 AM  #2  
Senior Member Joined: Mar 2009 Posts: 318 Thanks: 0  Quote:
You've rewritten the equation as 0 = y^2 + 4y + (4 + 2x  x^2) = 0  so a = 1, b = 4, and c = 4 + 2x  x^2  plugged "a", "b", and "c" into the Quadratic Formula, and... then what? Please be complete. Thank you!  
May 12th, 2009, 08:16 AM  #3 
Newbie Joined: Nov 2008 Posts: 9 Thanks: 0  Re: Quadratic Formula
It looks like you were assigned to plot the hyperbola given by the equation. As stated by Stapel, use the quadratic formula to solve for y and you will get something like y = a + (b)^2. Then you can use your calculator to plot the hyperbola. Remember there will be two equations required since there is a + b term. I'll let you work the math. 

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