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April 24th, 2009, 08:30 AM  #1 
Newbie Joined: Apr 2009 Posts: 3 Thanks: 0  Beginning algebra 2.5 formulas
Hi, I need help with math. I'm taking Beginning algebra right now. I'm stuck on Formulas 3. The formula for the area of a triangle is A = 1/2ab, where b is the base of the triangle and a is the altitude of the triangle. A) Use this formula to find the base of a triangle that has an area of 60 square meters and an altitude of 12 meters. b) Use this formula to find the altitude of a triangle that has an area of 88 square meters and a base of 11 meters.  7. A = 1/2bh solve for b 
April 24th, 2009, 08:36 AM  #2  
Senior Member Joined: Mar 2009 Posts: 318 Thanks: 0  Quote:
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If you get stuck, please reply showing how far you have gotten. Thank you!  
April 24th, 2009, 11:16 AM  #3  
Newbie Joined: Jan 2009 Posts: 7 Thanks: 0  Re: Beginning algebra 2.5 formulas
Let's make it clear that the formula is A = (1/2)ab or you could say ab/2. Quote:
A = 60, a = 12, find b Next write the equation with the values: 60 = (1/2)12b or 60 = 6b. I think you can get it from there. Quote:
Put values into your variables: A = 88, b = 11, find a Next writ the equation with the values: 88 = (1/2)a(11) Now divide both sides by 11 and you get: 8 = (1/2)a Now multiply both sides by 2 for the answer. Quote:
multiply both sides by 2 2A = 2(1/2)bh now simplify: 2A = bh now divide both sides by h. I'll leave it to you.  

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