My Math Forum Beginning algebra 2.5 formulas
 User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

 April 24th, 2009, 08:30 AM #1 Newbie   Joined: Apr 2009 Posts: 3 Thanks: 0 Beginning algebra 2.5 formulas Hi, I need help with math. I'm taking Beginning algebra right now. I'm stuck on Formulas 3. The formula for the area of a triangle is A = 1/2ab, where b is the base of the triangle and a is the altitude of the triangle. A) Use this formula to find the base of a triangle that has an area of 60 square meters and an altitude of 12 meters. b) Use this formula to find the altitude of a triangle that has an area of 88 square meters and a base of 11 meters. -------------------------------------------------------------------------------------------------------------------------------------------------------- 7. A = 1/2bh solve for b
April 24th, 2009, 08:36 AM   #2
Senior Member

Joined: Mar 2009

Posts: 318
Thanks: 0

Quote:
 Originally Posted by Valiant 3. The formula for the area of a triangle is A = 1/2ab, where b is the base of the triangle and a is the altitude of the triangle. A) Use this formula to find the base of a triangle that has an area of 60 square meters and an altitude of 12 meters.
Plug "60" in for "A". Plug "12" in for "a". Solve for "b".

Quote:
 Originally Posted by Valiant b) Use this formula to find the altitude of a triangle that has an area of 88 square meters and a base of 11 meters.
Plug "88" in for "A". Plug "11" in for "b". Solve for "a".

Quote:
 Originally Posted by Valiant 7. A = 1/2bh solve for b
Multiply through by 2. Divide through by h. Simplify to get the required result.

If you get stuck, please reply showing how far you have gotten. Thank you!

April 24th, 2009, 11:16 AM   #3
Newbie

Joined: Jan 2009

Posts: 7
Thanks: 0

Re: Beginning algebra 2.5 formulas

Let's make it clear that the formula is A = (1/2)ab or you could say ab/2.

Quote:
 A) Use this formula to find the base of a triangle that has an area of 60 square meters and an altitude of 12 meters.
First put values into your variables:
A = 60, a = 12, find b
Next write the equation with the values:
60 = (1/2)12b or 60 = 6b.
I think you can get it from there.

Quote:
 b) Use this formula to find the altitude of a triangle that has an area of 88 square meters and a base of 11 meters.
Again: A = (1/2)ab
Put values into your variables:
A = 88, b = 11, find a
Next writ the equation with the values:
88 = (1/2)a(11)
Now divide both sides by 11 and you get:
8 = (1/2)a
Now multiply both sides by 2 for the answer.

Quote:
 7. A = 1/2bh solve for b
A = (1/2)bh solve for b
multiply both sides by 2
2A = 2(1/2)bh
now simplify:
2A = bh
now divide both sides by h. I'll leave it to you.

 Tags algebra, beginning, formulas

Search tags for this page

,

,

,

,

,

,

### (2a-b)*(2a-b) solve

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post markys Algebra 2 January 14th, 2011 08:08 AM empiricus Algebra 3 December 14th, 2009 10:40 PM NeuroFuzzy Calculus 4 September 23rd, 2009 04:51 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top

Copyright © 2018 My Math Forum. All rights reserved.