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 April 23rd, 2009, 02:56 PM #1 Newbie   Joined: Apr 2009 Posts: 3 Thanks: 0 Rewrite the expression as an algebraic expression in x sin(2sin^-1x) *Note sine^-1 is sin inverse sin2x=2sinxcosx Drawing a triangle I found side a=x b=sq root (1-x^2) and c=1 Based on the triangle, I found cos to be sq root (1-x^2) so sin2x=2*x/1*sq root (1-x^2)=2xsqroot(1-x^2) Is the answer 2xsqroot(1-x^2)
 April 24th, 2009, 05:06 AM #2 Global Moderator   Joined: Dec 2006 Posts: 19,994 Thanks: 1856 Yes, that's correct.

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