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April 23rd, 2009, 01:56 PM  #1 
Newbie Joined: Apr 2009 Posts: 3 Thanks: 0  Rewrite the expression as an algebraic expression in x
sin(2sin^1x) *Note sine^1 is sin inverse sin2x=2sinxcosx Drawing a triangle I found side a=x b=sq root (1x^2) and c=1 Based on the triangle, I found cos to be sq root (1x^2) so sin2x=2*x/1*sq root (1x^2)=2xsqroot(1x^2) Is the answer 2xsqroot(1x^2) 
April 24th, 2009, 04:06 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,058 Thanks: 1618 
Yes, that's correct.


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