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 July 4th, 2015, 01:28 PM #1 Newbie   Joined: Jul 2015 From: California Posts: 5 Thanks: 0 Solve for X Can someone help show the process? Solve for X 3^(5x+2) = 27^(x-4) Note: the answer is x = -7 July 4th, 2015, 02:05 PM   #2
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Quote:
 Originally Posted by jimbodot Can someone help show the process? Solve for X 3^(5x+2) = 27^(x-4) Note: the answer is x = -7
$\displaystyle 3^{5x+2} = (3^3)^{x-4}$

use the appropriate rule re: exponents on the right side of the equation and match up the equal exponents ... July 24th, 2015, 04:44 PM #3 Newbie   Joined: Jul 2015 From: Serbia Posts: 8 Thanks: 1 $\begin{array}{l} {3^{5x + 2}} = {27^{x - 4}}\\ {3^{5x + 2}} = {\left( {{3^3}} \right)^{x - 4}}\\ {3^{5x + 2}} = {3^{3\left( {x - 4} \right)}}\\ {3^{5x + 2}} = {3^{3x - 12}}\\ 5x + 2 = 3x - 12\\ 5x - 3x = - 12 - 2\\ 2x = - 14\\ x = - \frac{{14}}{2} = - 7 \end{array}$ July 24th, 2015, 06:42 PM #4 Senior Member   Joined: May 2015 From: Varanasi Posts: 110 Thanks: 5 Math Focus: Calculus The equation will simplify to 5x+2=3x-12 on solving you will get, x=-7 Tags solve Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post gen_shao Algebra 12 November 2nd, 2014 06:11 AM

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