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April 6th, 2009, 01:35 AM   #1
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integrating factor method

this is the end part of a question and i dont understand the final integrating part.

now Y.IF = / Q.IF dX (/ = THE INTEGRATION SIGN)

THEREFORE Y (1-X^2)^1/2 = / (1/1-X^2).(1-X^2)^1/2 dX

Y.(1-X^2)^1/2 = / (1/(1-X^2)^1/2 dX

/ (1/(1-X^2)^1/2) dX = SIN^-1 X + C

Y.(1-X^2)^1/2 = SIN^-1 X + C



The bit that i do not get is how did they get from

/ (1/(1-x^2)^1/2) dX = sin^-1 x + C

i cant see how they integrated to get to sin-1 x, is there a method that i do not know?

thank you for helping!
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April 6th, 2009, 11:28 AM   #2
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