My Math Forum Problem

 Algebra Pre-Algebra and Basic Algebra Math Forum

 June 2nd, 2015, 10:27 PM #41 Banned Camp   Joined: May 2015 From: Casablanca Posts: 36 Thanks: 7 $2x-7=5x+6$. We'll solve this equation in steps: 1- Get rid of $2x$ by subtracting $2x$ in both sides: $(2x-7)-2x=(5x+6)-2x$ 2-Get rid of brackets and put numbers having x's one next the other: $2x-2x-7=5x-2x+6$ 3-You see that $2x-2x=0$ and $-7$ is left alone. In the other side $5x-2x=3x$. 4-From step $3$ the equation rearranges to: $-7=3x+6$. 5-We must cancel out $6$ in this step. To do so, we add the opposite of $6$ in both sides, which is $-6$: $-7-6=3x+6-6$. Note that $6-6=0$. 6-The equation becomes: $-13=3x$ or $3x=-13$ 7-Get rid of $3$. To do so, divide both sides by $3$: $\dfrac{3x}{3}=-\dfrac{13}{3}$. Note that $\dfrac{3x}{3}=\dfrac{3}{3}x=1*x=x$. $x=-\dfrac{13}{3}$ Hope that helped. Last edited by Assayid; June 2nd, 2015 at 10:35 PM.
June 3rd, 2015, 08:15 AM   #42
Member

Joined: May 2015
From: O

Posts: 34
Thanks: 0

Quote:
 Originally Posted by Assayid $2x-7=5x+6$. We'll solve this equation in steps: 1- Get rid of $2x$ by subtracting $2x$ in both sides: $(2x-7)-2x=(5x+6)-2x$ 2-Get rid of brackets and put numbers having x's one next the other: $2x-2x-7=5x-2x+6$ 3-You see that $2x-2x=0$ and $-7$ is left alone. In the other side $5x-2x=3x$. 4-From step $3$ the equation rearranges to: $-7=3x+6$. 5-We must cancel out $6$ in this step. To do so, we add the opposite of $6$ in both sides, which is $-6$: $-7-6=3x+6-6$. Note that $6-6=0$. 6-The equation becomes: $-13=3x$ or $3x=-13$ 7-Get rid of $3$. To do so, divide both sides by $3$: $\dfrac{3x}{3}=-\dfrac{13}{3}$. Note that $\dfrac{3x}{3}=\dfrac{3}{3}x=1*x=x$. $x=-\dfrac{13}{3}$ Hope that helped.
Why you got banned?

 June 3rd, 2015, 08:36 AM #43 Member   Joined: Jun 2015 From: Casablanca Posts: 47 Thanks: 3 Well, I pointed to a link out of general help, and mods banned me seeing it as a commercial spam.
June 3rd, 2015, 08:47 AM   #44
Member

Joined: May 2015
From: O

Posts: 34
Thanks: 0

Quote:
 Originally Posted by Mohajir Well, I pointed to a link out of general help, and mods banned me seeing it as a commercial spam.
Ah I see. WB! Thanks for the help!

 June 3rd, 2015, 10:17 AM #45 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Well Mathlover, I see you "live nowhere"; perhaps you can move to Banned Camp" too?!
June 3rd, 2015, 12:39 PM   #46
Member

Joined: May 2015
From: O

Posts: 34
Thanks: 0

Quote:
 Originally Posted by Mohajir Well, I pointed to a link out of general help, and mods banned me seeing it as a commercial spam.
I'm confuse why and how would you know if the answer is a negative?

June 3rd, 2015, 12:41 PM   #47
Member

Joined: May 2015
From: O

Posts: 34
Thanks: 0

Quote:
 Originally Posted by Denis Well Mathlover, I see you "live nowhere"; perhaps you can move to Banned Camp" too?!
Why is that?

June 3rd, 2015, 01:05 PM   #48
Member

Joined: Jun 2015
From: Casablanca

Posts: 47
Thanks: 3

Quote:
 Originally Posted by Mathlover44 I'm confuse why and how would you know if the answer is a negative?
I got a message from mods.
Hey, Mathlover44, don't bother yourself with it anymore. And thanks for your concern.

 June 3rd, 2015, 01:22 PM #49 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038 Please...can someone close this thread...

 Tags problem

 Thread Tools Display Modes Linear Mode

 Contact - Home - Forums - Cryptocurrency Forum - Top