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 Algebra Pre-Algebra and Basic Algebra Math Forum

 May 27th, 2015, 01:59 AM #1 Senior Member   Joined: Aug 2014 From: Mars Posts: 101 Thanks: 9 Direct variation I'm currently working through my algebra notes, because my calculus book told me I would be lost without an understanding of algebra. I've come to the conclusion that I was drunk when writing my notes, lol. Here is what I wrote: $\displaystyle "if" \frac{12}{3}=4 "and" \frac{a}{b}=k "then" kb = a "and"4 \cdot 3 = k "and"\frac{a}{16} = 4 "so" 4 \cdot 16 = 64$ I believe I was right up until $\displaystyle 4 \cdot 3 = k$, which should have been $\displaystyle 12 \div 3 = k$ and the rest needs correction too......... But given I am so far off, help  May 27th, 2015, 02:31 AM #2 Math Team   Joined: Nov 2014 From: Australia Posts: 689 Thanks: 244 Maybe what you were trying to write was "Given that $\dfrac{a}{b} = k$, then $a = 12$ and $b = 3$ implies $k = 4$." and "If $\dfrac{a}{16} = 4$, then $a = 4\cdot 16 = 64$. If your notes are supposed to be a single thread of logic, then I don't understand it at all. Especially why $4\cdot3 = k$ is followed by $\dfrac{a}{16} = 4$. Tags direct, variation Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Roli Abstract Algebra 1 July 8th, 2014 10:22 AM chelsf123 Algebra 5 August 17th, 2013 07:56 AM meghraj Algebra 4 August 8th, 2012 06:50 PM prashantakerkar Algebra 3 November 14th, 2011 11:11 PM empiricus Algebra 0 September 19th, 2011 01:10 PM

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