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 May 21st, 2015, 03:04 AM #1 Member   Joined: Jan 2015 From: Norway Posts: 95 Thanks: 1 Perform the division and do the answers as easy as possible Task 1.33 D) (2x^2-4)/(x-1) : (2)/(x-1) = (2x^2-4*(x-1))/((x-1)*2)= (2(x^2-2) * (x-1) (x+1)) / ((x+1) (x-1) *2) = (2x^2 -2 * x^2 - 1^2)/(x^2 - 1^2 * 2) I think what happens here is that the 2x-2 turns into 0x^2 which is x^2 and i think some of the letters and numbers get shorten. I think x^2 - - 1 ^2 get shorten and removed from the tasks in both sides. So that we end up with (x^2)/(2) and then we change sides of 2 so that we get x^2 (-2) = x^2 -2. Did i do this task correctly? May 21st, 2015, 05:35 AM #2 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,157 Thanks: 732 Math Focus: Physics, mathematical modelling, numerical and computational solutions This is how I would do it: $\displaystyle \frac{2x^2 - 4}{x-1} \div \frac{2}{x-1}$ $\displaystyle =\frac{2(x^2 - 2)}{x-1} \cdot \frac{x-1}{2}$ $\displaystyle =\frac{\cancel{2}(x^2 - 2)}{\cancel{x-1}} \cdot \frac{\cancel{x-1}}{\cancel{2}}$ $\displaystyle = x^2-2$ Tags answers, division, easy, perform Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post miran97 Algebra 4 May 30th, 2013 11:06 AM greg9o Calculus 1 January 27th, 2009 06:13 PM wilso793 Algebra 1 January 19th, 2009 09:31 AM

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