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May 21st, 2015, 03:04 AM  #1 
Member Joined: Jan 2015 From: Norway Posts: 95 Thanks: 1  Perform the division and do the answers as easy as possible
Task 1.33 D) (2x^24)/(x1) : (2)/(x1) = (2x^24*(x1))/((x1)*2)= (2(x^22) * (x1) (x+1)) / ((x+1) (x1) *2) = (2x^2 2 * x^2  1^2)/(x^2  1^2 * 2) I think what happens here is that the 2x2 turns into 0x^2 which is x^2 and i think some of the letters and numbers get shorten. I think x^2   1 ^2 get shorten and removed from the tasks in both sides. So that we end up with (x^2)/(2) and then we change sides of 2 so that we get x^2 (2) = x^2 2. Did i do this task correctly? 
May 21st, 2015, 05:35 AM  #2 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 2,150 Thanks: 730 Math Focus: Physics, mathematical modelling, numerical and computational solutions 
This is how I would do it: $\displaystyle \frac{2x^2  4}{x1} \div \frac{2}{x1}$ $\displaystyle =\frac{2(x^2  2)}{x1} \cdot \frac{x1}{2}$ $\displaystyle =\frac{\cancel{2}(x^2  2)}{\cancel{x1}} \cdot \frac{\cancel{x1}}{\cancel{2}}$ $\displaystyle = x^22$ 

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