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February 4th, 2009, 05:28 PM   #1
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writing the values of an angle?

Okay I understand the majority of this problem, but there's just one part that I don't understand!

Problem: Given that x is in Quadrant II, and cscx=3, find the values of all six trigonometric functions of x.

So when i draw the triangle in Quadrant II, I got y=1, r=3, and on the key x=square root of 8. I understand how y and r were found, but how was x found?
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February 4th, 2009, 07:19 PM   #2
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Pythagoras's theorem requires x^2 + y^2 = r^2, but x is negative for points in the second (or third) quadrant.
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February 4th, 2009, 07:31 PM   #3
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Re: writing the values of an angle?

perfect thank you!
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