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 May 20th, 2015, 05:01 AM #1 Member   Joined: Jan 2015 From: Norway Posts: 95 Thanks: 1 multiply the fractions and make the answer as easy as possible (almost done) 1.32 D) a^2-b^2/2x^2-2y^2 * x+y/3a-3b = a^2-b^2*x+y/2x^2-2y^2*3a*3b What happens now is that you shorten the fraction, you shorten a and b to remove the 3a and 3b to be 3 and 3. You shorten the fraction of x and y to remove them and make 2x^2 - 2y^2 to be 2x - 2y. What happens now is this a-b/2x-2y*3*3 What you do now is multiply 2x with 3 and multiply 2y with 3 = a+b/2*3*x-2*3*y Making it = a+b/6x-6y. To end it with a+b/6(x-y). I am done with the task, but there are one thing I don't understand. Why and how did a-b change into a+b? After I know this, I understand the whole task. Last edited by skipjack; May 20th, 2015 at 12:19 PM. May 20th, 2015, 10:01 AM #2 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039 You've been told a few times to use BRACKETS when necessary; do you not understand what that means? For example, your "a^2-b^2/2x^2-2y^2 * x+y/3a-3b" should be: (a^2 - b^2) / (2x^2 - 2y^2) * (x + y) / (3a-3b) Make SURE you understand why...else you'll keep being in trouble... The (a - b) did NOT change into (a + b). What happened is the (a - b)'s all cancelled out, but the (a + b) didn't. May 21st, 2015, 02:18 AM   #3
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Quote:
 Originally Posted by Denis You've been told a few times to use BRACKETS when necessary; do you not understand what that means? For example, your "a^2-b^2/2x^2-2y^2 * x+y/3a-3b" should be: (a^2 - b^2) / (2x^2 - 2y^2) * (x + y) / (3a-3b) Make SURE you understand why...else you'll keep being in trouble... The (a - b) did NOT change into (a + b). What happened is the (a - b)'s all cancelled out, but the (a + b) didn't.
ah, thanks, i understand brackets now.  Tags answer, easy, fractions, make, multiply Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Timios New Users 1 January 27th, 2014 08:54 AM myanthnkz04 Probability and Statistics 1 January 7th, 2014 06:25 PM mrhesham Academic Guidance 1 December 29th, 2010 07:10 PM Joachim Calculus 1 November 27th, 2008 08:20 AM Timios Elementary Math 0 December 31st, 1969 04:00 PM

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