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February 3rd, 2009, 01:14 PM  #1 
Newbie Joined: Feb 2009 Posts: 2 Thanks: 0  Hard Question for Me
Hi, been having problems with this question.. I got to be honest.. I need this to help me get through my college course, but it's a high school question.. just find it really hard.. thanks in advance: 1.) Find the equation of a straight line that passes through the point (3, 1) and is perpendicular to the line y = 5x  2. Give your answer in the form ax + by + c = 0 Thanks, if I find anymore difficult.. I will shout back. Thanks, Dan 
February 3rd, 2009, 02:50 PM  #2 
Senior Member Joined: Sep 2008 Posts: 116 Thanks: 0  Re: Hard Question for Me
Point slope form of a line is given by: y  y1 = m (x  x1) You are given a point (3, 1) and just need to find the slope. You know the slope of the new line is perpindicular to the line y = 5x  2 which has a slope of 5. A perpindicular slope is the negative recipricole of that; so 1/5. Plug in these values to the point slope equation of a line: y  (1) = 1/5 ( x  3) y + 1 = (x  3) / 5 Then, rewrite the equation in standard form, the form being asked for: 5 (y + 1) = (x 3) 5y +5 = 3  x 5y + x + 5 3 = 0 5y + x +2 = 0 Wrote this all in a rush, headed out of my office for the day, though if you have a question, feel free to ask and I'll reply later tonight at my house. 
February 4th, 2009, 10:23 AM  #3 
Newbie Joined: Feb 2009 Posts: 2 Thanks: 0  Re: Hard Question for Me
Thank you good sir 

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