My Math Forum Shortening a fraction question

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 May 10th, 2015, 09:15 AM #1 Member   Joined: Jan 2015 From: Norway Posts: 95 Thanks: 1 Shortening a fraction question Task 1.23 Shorten the fractions A) 100/6= I did 2*50/2*3 and i then removed the 2 numbers and got 50/3 = 16.67 But the book says 100/6= 2*2*5*5/2*3= 50/3 Is my way also correct and acceptable or is only the way the book showed correct and acceptable?
 May 10th, 2015, 12:33 PM #2 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 Both methods are valid (in fact, they are almost the same) and give the same answer.
May 10th, 2015, 08:27 PM   #3
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Quote:
 Originally Posted by Zman15 Task 1.23 Shorten the fractions A) 100/6= I did 2*50/2*3 $\displaystyle \ \ \ \ \$2*50/(2*3) and i then removed the 2 numbers and got 50/3 = 16.67 But the book says 100/6= 2*2*5*5/2*3$\displaystyle \ \ \ \ \$2*2*5*5/(2*3) = 50/3 Is my way also correct and acceptable or is only the way the book showed correct and acceptable?
Use parentheses around your denominators when you have products
as I retyped, because of the Order of Operations.

With your first expression entered in a calculator, for example, a value of 150 would be returned,
and for your second expression, a value of 150 would also be returned.

 May 20th, 2015, 02:49 AM #4 Newbie   Joined: May 2015 From: usa Posts: 6 Thanks: 0 Math Focus: trigonometry HELLO, I'm including lots of extra versions of the expression to show how you can write the same expression in different ways. How to shorten this fraction? R1+R2 divided by 1/R1+1/R2 We can use a common trick for simplifying a fraction, multiplying by an expression equal to R1+R21/R1+1/R2=R1R2(R1+R2)R1R2(1/R1+1/R2)=R1R2(R1+R2)R2+R1=R1R2

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