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May 10th, 2015, 09:15 AM   #1
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Shortening a fraction question

Task 1.23 Shorten the fractions
A) 100/6= I did 2*50/2*3 and i then removed the 2 numbers and got 50/3 = 16.67
But the book says 100/6= 2*2*5*5/2*3= 50/3

Is my way also correct and acceptable or is only the way the book showed correct and acceptable?
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May 10th, 2015, 12:33 PM   #2
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Both methods are valid (in fact, they are almost the same) and give the same answer.
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May 10th, 2015, 08:27 PM   #3
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Quote:
Originally Posted by Zman15 View Post
Task 1.23 Shorten the fractions
A) 100/6= I did

2*50/2*3 $\displaystyle \ \ \ \ \ $2*50/(2*3)

and i then removed the 2 numbers and got 50/3 = 16.67
But the book says 100/6=

2*2*5*5/2*3$\displaystyle \ \ \ \ \ $2*2*5*5/(2*3)

= 50/3

Is my way also correct and acceptable or is only the way the book showed correct and acceptable?
Use parentheses around your denominators when you have products
as I retyped, because of the Order of Operations.

With your first expression entered in a calculator, for example, a value of 150 would be returned,
and for your second expression, a value of 150 would also be returned.
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May 20th, 2015, 02:49 AM   #4
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HELLO,

I'm including lots of extra versions of the expression to show how you can write the same expression in different ways.
How to shorten this fraction?
R1+R2 divided by 1/R1+1/R2

We can use a common trick for simplifying a fraction, multiplying by an expression equal to

R1+R21/R1+1/R2=R1R2(R1+R2)R1R2(1/R1+1/R2)=R1R2(R1+R2)R2+R1=R1R2
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