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 April 30th, 2015, 10:00 AM #1 Member   Joined: Feb 2014 Posts: 91 Thanks: 1 Where did this exponent come from? Not sure about this, please assist.
 April 30th, 2015, 10:37 AM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 2,924 Thanks: 1521 you were given ... $y^2=5-x^2$ $y = x-1$ substitute $(x-1)$ for $y$ in the first equation ... $(x-1)^2 = 5-x^2$
 April 30th, 2015, 10:39 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 You are given the two equations $\displaystyle x^2+ y^2= 5$ and $\displaystyle x- y= 1$. Subtrating $\displaystyle x^2$ from both sides of the first equation, $\displaystyle y^2= 5- x^2$ Adding y to both sides of the second equation, $\displaystyle x= 1+ y$. Subtracting 1 from both sides of that equation, $\displaystyle x- 1= y$ So we can replace y by x- 1 in $\displaystyle y^2= 5- x^2$: $\displaystyle (x- 1)^2= 5- x^2$. Essentially then the exponent, 2, in that equation come form the exponent on y in the equation $\displaystyle x^2+ y^2= 5$.
 May 1st, 2015, 07:21 PM #4 Senior Member     Joined: Nov 2010 From: Indonesia Posts: 2,001 Thanks: 132 Math Focus: Trigonometry If you are that confused, just write y = y between the second and the third line, hope you understand.

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