My Math Forum Fundamental Formula of Gambling

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 January 14th, 2009, 04:28 PM #1 Newbie   Joined: Jan 2009 Posts: 2 Thanks: 0 Fundamental Formula of Gambling Hi guys, I have a question... I have this formulae: log(1 - DC) N = ---------------- log(1 - p) I can find N if I have DC and p. But I can't figure out how to find DC if I have N and p. Is that possible? Cheers!
 January 14th, 2009, 06:46 PM #2 Senior Member   Joined: Jul 2008 Posts: 895 Thanks: 0 Re: Fundamental Formula of Gambling log(1 - DC) = N(log(1 - p)) Assuming base 10... 1 - DC = 10^[N(log(1 - p))] etc. Another approach uses the fact that log(1 - DC)/log(1 - p) = log(1 - DC) using base (1 - p).
 January 17th, 2009, 07:06 AM #3 Global Moderator   Joined: Dec 2006 Posts: 17,919 Thanks: 1383 log(1 - DC) = N log(1 - p) = log((1 - p)^N), so DC = 1 - (1 - p)^N.

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### fundamental formula of gambling

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