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January 14th, 2009, 04:28 PM  #1 
Newbie Joined: Jan 2009 Posts: 2 Thanks: 0  Fundamental Formula of Gambling
Hi guys, I have a question... I have this formulae: log(1  DC) N =  log(1  p) I can find N if I have DC and p. But I can't figure out how to find DC if I have N and p. Is that possible? Cheers! 
January 14th, 2009, 06:46 PM  #2 
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: Fundamental Formula of Gambling
log(1  DC) = N(log(1  p)) Assuming base 10... 1  DC = 10^[N(log(1  p))] etc. Another approach uses the fact that log(1  DC)/log(1  p) = log(1  DC) using base (1  p). 
January 17th, 2009, 07:06 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,066 Thanks: 1621 
log(1  DC) = N log(1  p) = log((1  p)^N), so DC = 1  (1  p)^N.


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