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January 8th, 2009, 06:07 PM   #1
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A little confused

ok it is obvious when u have x^2= 16 you just take the square root.

However i have encounter this in one of my problems-----t^.2=.763

thinking logically I should just raise .763 to the reciprocal of .2....right?????

so is the answer .2601

please clarify if I am wrong and could someone verify my thinking.
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January 8th, 2009, 11:50 PM   #2
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Your method is right, but the result is 0.258596528100043 (or 0.2586 approximately), not .2601.
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