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January 7th, 2009, 02:15 PM  #1 
Newbie Joined: Jan 2009 Posts: 2 Thanks: 0  Solve for 'x' algebraically, extremely difficult (advanced)?
I need to know how to algebraically solve for 'x' in this equation: Note: ' * ' denotes multiplication. 2^(e*x)x+2=0 Please, show all of your steps because no matter what I do, I wind up going back and fourth. The answer should be: x = ((2*e*log(2)Productlog((2^2e)*e*log(2))/(e*log(2))) x ? 0.285983 I don't even know what "Productlog" is. I've heard of it used in a Lambert Function, but that's for programming and whatnot, so it can't be the same. Grrr. Thanks. 
January 7th, 2009, 04:55 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,310 Thanks: 1981 
Yes, it can be! See this article.

January 11th, 2009, 05:10 PM  #3 
Senior Member Joined: May 2007 Posts: 402 Thanks: 0  Re: Solve for 'x' algebraically, extremely difficult (advanced)? 

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