My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum


Reply
 
LinkBack Thread Tools Display Modes
January 7th, 2009, 01:15 PM   #1
Newbie
 
Joined: Jan 2009

Posts: 2
Thanks: 0

Solve for 'x' algebraically, extremely difficult (advanced)?

I need to know how to algebraically solve for 'x' in this equation:

Note: ' * ' denotes multiplication.

-2^(e*x)-x+2=0

Please, show all of your steps because no matter what I do, I wind up going back and fourth.

The answer should be:

x = ((2*e*log(2)-Productlog((2^2e)*e*log(2))/(e*log(2)))

x ? 0.285983

I don't even know what "Productlog" is. I've heard of it used in a Lambert Function, but that's for programming and whatnot, so it can't be the same. Grrr.

Thanks.
IsenseHelp is offline  
 
January 7th, 2009, 03:55 PM   #2
Global Moderator
 
Joined: Dec 2006

Posts: 20,475
Thanks: 2039

Yes, it can be! See this article.
skipjack is offline  
January 11th, 2009, 04:10 PM   #3
Senior Member
 
Joined: May 2007

Posts: 402
Thanks: 0

Re: Solve for 'x' algebraically, extremely difficult (advanced)?





















milin is offline  
Reply

  My Math Forum > High School Math Forum > Algebra

Tags
advanced, algebraically, difficult, extremely, solve



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
Advanced Math: Algorithm to Solve an Optimal Set forkconfig Applied Math 1 February 6th, 2014 02:25 PM
How to solve these problems algebraically? GrannySmith Algebra 2 January 5th, 2014 03:50 PM
solve algebraically drewm Algebra 2 July 4th, 2011 03:06 PM
HOw to solve the difficult level of this game? problem_solver123 Algebra 2 September 5th, 2009 09:37 PM
An extremely difficult question on coordinate geometry. Zan Geometry 2 May 23rd, 2008 07:22 AM





Copyright © 2019 My Math Forum. All rights reserved.