February 23rd, 2015, 04:58 PM  #1 
Senior Member Joined: Jan 2015 From: USA Posts: 107 Thanks: 2  logarithms
Im having trouble with this log problem. please help!

February 23rd, 2015, 06:41 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,880 Thanks: 1503 
$\log_2(x1)\log_4(x+3)=\frac{1}{2}$ Use a change of base ... $\log_4{a}=\frac{\log_2{a}}{\log_2{4}}$ Also note $\frac{1}{2}=\log_2{\sqrt{2}}$ Once you get every log in base 2, then use your log properties to set up an equation in the form $\log_2{p}=\log_2{q} \implies p=q$ 
February 23rd, 2015, 07:34 PM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Hello, matisolla! Quote:  

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