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 Algebra Pre-Algebra and Basic Algebra Math Forum

 December 26th, 2014, 05:04 PM #1 Newbie   Joined: Dec 2014 From: Australia Posts: 1 Thanks: 0 Dividing by 0 y=-2x/z is undefined at z=0 but if you multiply the z over to the other side: zy=-2x, at z=0. is 0=-2x => x=0 Why is this? Would this work on concepts like: y=x/0 => 0=x ? [Thanks in advance!] Last edited by skipjack; December 26th, 2014 at 06:45 PM. December 26th, 2014, 05:38 PM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 7,689 Thanks: 2669 Math Focus: Mainly analysis and algebra You can't say that $x = 0$ because $y$ is undefined by the equation $yz = -2x$ when $z = 0$. If $y$ is experiencing unbounded growth as $z \to 0$ then $x$ may not be zero at $z = 0$, but undefined (possibly with a finite limit). And no, it doesn't work on $y = \frac{x}{0}$. December 26th, 2014, 06:57 PM #3 Senior Member   Joined: Jan 2014 From: The backwoods of Northern Ontario Posts: 393 Thanks: 71 Whereas division by 0 is undefined, suppose that we define ONE exception. Suppose we define $\displaystyle \frac {0}{0}$ as $\displaystyle 0$. Would that eliminate the problem, afk? December 26th, 2014, 09:18 PM #4 Global Moderator   Joined: Dec 2006 Posts: 21,019 Thanks: 2254 No. Your original post and v8archie's reply were both incorrect. Using x, y and z as Cartesian coordinates, the equation zy = -2x defines a surface that intersects the x-y plane in the entire y-axis. If one removes the y-axis from that surface, the resulting surface corresponds to the equation y = -2x/z. Tags dividing, dividing by 0, moving the 0? Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post Chikis Elementary Math 4 March 12th, 2013 09:03 AM maxgeo Algebra 1 September 12th, 2012 07:18 AM Jo15 Calculus 7 January 1st, 2012 07:51 PM :) Sidways8 :) Number Theory 14 February 16th, 2011 04:44 PM triplekite Algebra 2 January 3rd, 2011 09:11 AM

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