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December 16th, 2014, 02:31 PM  #1 
Newbie Joined: Dec 2014 From: askard Posts: 9 Thanks: 0  linear programming problem 2
There are 6 pieces of wooden boards of a furniture craftsman and has 28 hours of free time. Sells two types of libraries by the board. Type I library requires 2 wooden boards and 7 hours; The library requires a type II 1 plate and 8 hours. The selling price of 120,000 \$ Type I library. The price is 80,000 \$ type II library. According to want to maximize sales revenue Furnishers must be purchased from both models make how many of each? Install problem as a linear programming model. Last edited by greg1313; December 16th, 2014 at 02:34 PM. 
December 17th, 2014, 07:13 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 19,982 Thanks: 1853 
What does "plate" mean?

December 17th, 2014, 10:18 PM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407  Hello, kalli1! Your English is not too accurate. I'll modify the wording for simplicity. Quote:
Let $x$ = number of type A tables: $\:x \ge 0$ Let $y$ = number of type B tables: $\:y \ge 0$ We have: $\quad \begin{array}{cccc} & \text{boards} & \text{hours} & \text{Revenue} \\ \hline A & 2x & 7x & 1200x \\ B & y & 8y & 800y \\ \hline & 6 & 28 \\ \hline \end{array}$ In Quadrant I, we must graph and shade: $\quad\begin{array}{ccc} 2x + y & \le & 6 \\ 7x + 8y &\le & 28 \end{array}$ Then find the coordinates of the vertices of the shaded area. Then substitute them into the Revenue function: $\:R \;=\;1200x+800y$ $\quad$ and determine which produces maximum revenue.  
December 18th, 2014, 04:36 AM  #4 
Newbie Joined: Dec 2014 From: askard Posts: 9 Thanks: 0 
sorry for my english and thank you so much.


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