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November 16th, 2014, 12:52 PM  #1 
Newbie Joined: Nov 2014 From: georgia Posts: 1 Thanks: 0  hello all :) I don't know where I can put algorithms and please don't block this ))
F(4) = 17 F(n) = 2F(n1) + 2n there is a little algorithm and can you solve it .. I solved it and in my opinion it is F(n) = F(n) = 2^(n4)*F4 + (5+n)(n4) that one, but someone says that this is not true. Can you solve this and explain why?? Thanks in advance. Last edited by skipjack; November 16th, 2014 at 02:40 PM. 
November 16th, 2014, 02:50 PM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,089 Thanks: 1902 
That's not quite right. The solution is F(n) = (F(4) + 12)2^(n4)  2n  4.

November 22nd, 2014, 12:45 AM  #3  
Newbie Joined: Nov 2014 From: HK Posts: 3 Thanks: 1  I don't get it Quote:
17 = 2F(41) + 2(4) 17 = 6F + 8 9 = 6F F = 3/2  

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algorithms, block, put 
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