User Name Remember Me? Password

 Algebra Pre-Algebra and Basic Algebra Math Forum

 October 30th, 2014, 01:55 PM #1 Newbie   Joined: Oct 2014 From: London Posts: 27 Thanks: 0 Help with these surd equations?! I have these equations 1.$\displaystyle \frac{5^2x5^{-3}}{5^{-4}x5^{6}}$ 2.$\displaystyle \frac{(x^5y^3)^4}{x^3y^2}$ 3.$\displaystyle \frac{\sqrt{6}+4}{\sqrt{4}}$ Any help? October 30th, 2014, 05:22 PM   #2
Math Team

Joined: Jul 2011
From: Texas

Posts: 3,031
Thanks: 1620

Quote:
 Originally Posted by mathsheadache I have these equations 1.$\displaystyle \frac{5^2x5^{-3}}{5^{-4}x5^{6}}$ 2.$\displaystyle \frac{(x^5y^3)^4}{x^3y^2}$ 3.$\displaystyle \frac{\sqrt{6}+4}{\sqrt{4}}$ Any help?
1.$\displaystyle \frac{5^2x5^{-3}}{5^{-4}x5^{6}}$

the x factors in the numerator & denominator divide out to 1

numerator ... $\displaystyle 5^2 \cdot 5^{-3} = 5^{-1}$

denominator ... $\displaystyle 5^{-4} \cdot 5^6 = 5^2$

$\displaystyle \frac{5^{-1}}{5^2} = 5^{-1-2} = 5^{-3} = \frac{1}{5^3}$

2. $\displaystyle \frac{(x^5y^3)^4}{x^3y^2}$

$\displaystyle \frac{x^{20}y^{12}}{x^3y^2}$ ... now use the rule for division for exponents

3. $\displaystyle \frac{\sqrt{6}+4}{\sqrt{4}}$

come on ... what is $\displaystyle \sqrt{4}$ ? Tags equations, surd mathsforum.co surds

Click on a term to search for related topics.
 Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post jessjans11 Elementary Math 9 July 20th, 2014 07:24 AM Monokuro Trigonometry 2 May 6th, 2014 07:14 AM mathematics101010 Algebra 6 August 4th, 2013 04:00 AM sachinrajsharma Algebra 15 February 23rd, 2013 06:51 PM prescott2006 Calculus 0 March 9th, 2008 11:00 AM

 Contact - Home - Forums - Cryptocurrency Forum - Top      