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 October 19th, 2014, 09:49 AM #1 Newbie   Joined: Oct 2014 From: London Posts: 27 Thanks: 0 Calculate the radius of the cylinder if its height is 2.80m? The total SA of a closed cylindrical container is 20.0cm^2. Calculate the radius of the cylinder if its height is 2.80m I know the SA formula is 2pir+2pirh=20cm but from here? October 19th, 2014, 10:45 AM   #2
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 Originally Posted by mathsheadache The total SA of a closed cylindrical container is 20.0cm^2. Calculate the radius of the cylinder if its height is 2.80m I know the SA formula is 2pir+2pirh=20cm but from here?
correction ...

$\displaystyle A = 2\pi r^2 + 2\pi r h$

sub in 2.8 for h and 20 for A ... solve for r October 19th, 2014, 10:52 AM   #3
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 Originally Posted by skeeter correction ... $\displaystyle A = 2\pi r^2 + 2\pi r h$ sub in 2.8 for h and 20 for A ... solve for r
I am not so great with rearranging for r. There is always r^2 October 19th, 2014, 10:58 AM   #4
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 Originally Posted by mathsheadache I am not so great with rearranging for r. There is always r^2
for $\displaystyle ar^2 + br + c = 0$

$\displaystyle r = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$

look familiar? October 20th, 2014, 02:04 PM #5 Senior Member   Joined: Jul 2014 From: भारत Posts: 1,178 Thanks: 230 $\displaystyle \textbf{Hello, mathsheadache (However, maths is not a headache.)}$ $\displaystyle \textbf{We know,}$ $\displaystyle \textbf{Total Surface Area of a cylinder}=2 \pi r(r+h)$ $\displaystyle \textbf{Here, TSA is given to be 20} \textbf{cm}^{2}$ $\displaystyle \textbf{Height = 2.80 m but we need to be consistent with units, so let's convert in cm.}$ $\displaystyle \textbf{So, h = 280 cm.}$ $\displaystyle \textbf{According to the question,}$ $\displaystyle 2 \pi r^{2} + 2 \pi r \times 280 = 20 \ \ \textbf{cm}^{2}$ $\displaystyle \textbf{Divide each term by}\ \ 2 \pi$ $\displaystyle r^{2} + 280r = 3.183$ $\displaystyle \textbf{Rearrange this into:}$ $\displaystyle r^{2} + 280r - 3.183 = 0$ $\displaystyle \textbf{A quadratic equation can be solved in three ways :}$ $\displaystyle \textbf{1. By middle-term-splitting method.} \\ \textbf{2. By completing the square.} \\ \textbf{3. By using the quadratic formula.}$ $\displaystyle \textbf{In this case, we use the Quadratic Formula :}$ $\displaystyle \textbf{A Quadratic Equation of the form } ax^{2}+bx+c=0 \ \ \textbf{can be solved by the following formula :}$ $\displaystyle x=-b \pm \frac{\sqrt{b^{2}-4ac}}{2a} \ \ \textbf{where x represents an unknown, and a, b, and c are constants with }a \neq 0$ $\displaystyle \textbf{If you solve that using the usual quadratic formula, the positive value for r is 0.01 cm.}$ $\displaystyle \textbf{Is the height = 2.80 m, or is it 2.80 cm?}$ $\displaystyle \textbf{If it is the latter, then :}$ $\displaystyle r^{2} + 2.8r - 3.183 = 0$ $\displaystyle \textbf{would give:}$ $\displaystyle r = 0.868 \ \ \textbf{cm}$ Last edited by Prakhar; October 20th, 2014 at 02:22 PM. October 20th, 2014, 07:38 PM   #6
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 Originally Posted by prakhar $\displaystyle \textbf{A Quadratic Equation of the form } ax^{2}+bx+c=0 \ \ \textbf{can be solved by the following formula :}$ $\displaystyle x=-b \pm \frac{\sqrt{b^{2}-4ac}}{2a} \ \ \textbf{where x represents an unknown, and a, b, and c are constants with }a \neq 0$
That should be $\displaystyle \ \ x \ = \ \dfrac{-b \pm \sqrt{b^{2}-4ac \ }}{2a}.$ Tags 280m, calculate, cylinder, height, radius Search tags for this page

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### the total surface of a closed cylindrincal container is 20 m. calculate the radius of the cylinder,height=2.80m

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