My Math Forum Determining n from the given factorial equation

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October 1st, 2014, 05:57 PM   #11
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 Originally Posted by Hoempa I admire your patience. On the board I'm a mod, he would probably have been banned already.
We really don't have an official policy here regarding making an effort, but yes on the other boards I admin, I would have slung the ban hammer some time ago.

Last edited by MarkFL; October 1st, 2014 at 06:00 PM.

 October 2nd, 2014, 01:46 AM #12 Newbie   Joined: Sep 2014 From: iasi Posts: 3 Thanks: 1 4(n+1)!=(n)!(2n-6)! Divide both sides by (n)! 4(n+1)! /(n)!=(2n-6)! Simplify the left hand side: 4n+4 = (2n-6)! Trial and error: minimum valid n value: 4. trying n=4: 20 = 2 False trying n=5: 24 = 4! ---> 24 = 24 True n=5 is the solution. Its uniqueness is guaranteed because the rate of change of the factorial (on the right) is greater than that of the linear function (on the left of the equal sign), for any integer greater than 5.

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