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September 19th, 2014, 04:53 PM   #1
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Dimensional Analysis

Hello,

I solved for the question below. Can you check this please?

A nitrogen molecule, N_2, is traveling through the air at a speed of 387 m/s. How long would it take for the molecule to travel 2.50 miles, assuming it does not crash into any other molecules or objects?


$\displaystyle 2.50 mi • \frac {1.609 m}{1 mi}•\frac {1s}{387m} = 0.01038 = 1.04 x 10-^2 s $
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September 19th, 2014, 06:14 PM   #2
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For constant speed, time is distance per velocity:

$\displaystyle t=\frac{2.5\text{ mi}}{387\,\dfrac{\text{m}}{\text{s}}}\cdot\frac{16 09.344\text{ m}}{1\text{ mi}}\approx10.4\text{ s}$

Do you see the error you made in your equivalence of meters to miles?

Last edited by MarkFL; September 19th, 2014 at 06:17 PM.
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September 19th, 2014, 06:40 PM   #3
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Oh I see! The 1.609 m should be 1609.344 m. Thank you so much for pointing that out to me
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