My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum

Thanks Tree1Thanks
  • 1 Post By ChristinaScience
LinkBack Thread Tools Display Modes
September 19th, 2014, 04:53 PM   #1
ChristinaScience's Avatar
Joined: Nov 2010

Posts: 97
Thanks: 1

Dimensional Analysis


I solved for the question below. Can you check this please?

A nitrogen molecule, N_2, is traveling through the air at a speed of 387 m/s. How long would it take for the molecule to travel 2.50 miles, assuming it does not crash into any other molecules or objects?

$\displaystyle 2.50 mi • \frac {1.609 m}{1 mi}•\frac {1s}{387m} = 0.01038 = 1.04 x 10-^2 s $
ChristinaScience is offline  
September 19th, 2014, 06:14 PM   #2
Senior Member
MarkFL's Avatar
Joined: Jul 2010
From: St. Augustine, FL., U.S.A.'s oldest city

Posts: 12,211
Thanks: 521

Math Focus: Calculus/ODEs
For constant speed, time is distance per velocity:

$\displaystyle t=\frac{2.5\text{ mi}}{387\,\dfrac{\text{m}}{\text{s}}}\cdot\frac{16 09.344\text{ m}}{1\text{ mi}}\approx10.4\text{ s}$

Do you see the error you made in your equivalence of meters to miles?

Last edited by MarkFL; September 19th, 2014 at 06:17 PM.
MarkFL is offline  
September 19th, 2014, 06:40 PM   #3
ChristinaScience's Avatar
Joined: Nov 2010

Posts: 97
Thanks: 1

Oh I see! The 1.609 m should be 1609.344 m. Thank you so much for pointing that out to me
Thanks from MarkFL
ChristinaScience is offline  

  My Math Forum > High School Math Forum > Algebra

analysis, dimensional

Thread Tools
Display Modes

Similar Threads
Thread Thread Starter Forum Replies Last Post
Dimensional Analysis ChristinaScience Algebra 10 September 12th, 2014 01:48 PM
Diffential elements and analysis dimensional Jhenrique Calculus 1 March 31st, 2014 01:02 PM
Tricky dimensional analysis Djordje8 Physics 0 February 10th, 2014 06:07 AM
Dimensional analysis (Weir Eq.) bofeity Physics 6 February 6th, 2012 08:13 PM
Dimensional analysis MasterOfDisaster Physics 6 June 9th, 2011 08:47 AM

Copyright © 2019 My Math Forum. All rights reserved.