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 September 19th, 2014, 04:53 PM #1 Member     Joined: Nov 2010 Posts: 97 Thanks: 1 Dimensional Analysis Hello, I solved for the question below. Can you check this please? A nitrogen molecule, N_2, is traveling through the air at a speed of 387 m/s. How long would it take for the molecule to travel 2.50 miles, assuming it does not crash into any other molecules or objects? $\displaystyle 2.50 mi • \frac {1.609 m}{1 mi}•\frac {1s}{387m} = 0.01038 = 1.04 x 10-^2 s$
 September 19th, 2014, 06:14 PM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs For constant speed, time is distance per velocity: $\displaystyle t=\frac{2.5\text{ mi}}{387\,\dfrac{\text{m}}{\text{s}}}\cdot\frac{16 09.344\text{ m}}{1\text{ mi}}\approx10.4\text{ s}$ Do you see the error you made in your equivalence of meters to miles? Last edited by MarkFL; September 19th, 2014 at 06:17 PM.
 September 19th, 2014, 06:40 PM #3 Member     Joined: Nov 2010 Posts: 97 Thanks: 1 Oh I see! The 1.609 m should be 1609.344 m. Thank you so much for pointing that out to me Thanks from MarkFL

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