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September 10th, 2014, 08:36 AM   #1
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find the remainder

The rest of the divisible
3^99 divide by 8
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September 10th, 2014, 08:46 AM   #2
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Check out this link :
http://www.wolframalpha.com/input/?i=%283^%2899%29%29%2F8
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September 10th, 2014, 08:52 AM   #3
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$$3^{99} \equiv 3(3^2)^{49} \equiv 3\cdot 9^{49} \equiv 3 \cdot 1^{49} \equiv 3 \cdot 1 \equiv 3 \pmod 8$$
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Last edited by v8archie; September 10th, 2014 at 08:58 AM.
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September 10th, 2014, 09:04 AM   #4
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Quote:
Originally Posted by prakhar View Post
Check out this link :
http://www.wolframalpha.com/input/?i=%283^%2899%29%29%2F8
Wolfram Alpha has failed you again, Prakhar. At least it's an acknowledged source this time.
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September 10th, 2014, 09:36 AM   #5
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Originally Posted by mared View Post
The rest of the divisible
3^99 divide by 8
I gave your thread a title that is not completely useless. Please make some kind of effort with your thread titles.
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