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September 9th, 2014, 09:05 AM   #1
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Help with my homework

Hi im having a lot of trouble with these questions. Can someone help me?

^ = power
v = root
/ = divide

1) Simplify w^1/2 x w^3/2 / w
2) Find the gradient of a straight line which is parallel to the line 2x -6y = 5
3) Simplify (2 - v3)(2+v3)
4)Rationalise the denominator of 1/2v3. Give your answer in the form va/b where a and b are integers.
5)Solve 9/10-x + 9/10+x = 5
6) V is directly propotional to the cube of x. When x=3, V=54. Find a formula for V in terms of x.
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September 9th, 2014, 09:14 AM   #2
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These are quite basic...have you been skipping math classes?
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September 9th, 2014, 09:18 AM   #3
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Math Focus: Calculus/ODEs
You will usually get help more promptly if you post no more than 2 questions per thread.

Let's begin with the first one:

$\displaystyle \frac{w^{\frac{1}{2}}\cdot w^{\frac{3}{2}}}{w}=w^{\frac{1}{2}}\cdot w^{\frac{3}{2}}\cdot w^{-1}$

Now, add the exponents...what do you get?
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September 9th, 2014, 09:25 AM   #4
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Originally Posted by Denis View Post
These are quite basic...have you been skipping math classes?
I'm 16. I from England, im starting a level's and this is my summer work. I need this by tomorrow because they might kick me out of the course if I wont do it... So its kinda important but i can't do these myself. If they are easy for then please help me...

Quote:
You will usually get help more promptly if you post no more than 2 questions per thread.

Let's begin with the first one:

w12⋅w32w=w12⋅w32⋅w−1

Now, add the exponents...what do you get?
I have no idea how to do these, I barely got into the a level with a B grade at GCSE...

Last edited by ONEnONLY; September 9th, 2014 at 09:33 AM.
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September 9th, 2014, 09:32 AM   #5
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Quote:
Originally Posted by MarkFL View Post
You will usually get help more promptly if you post no more than 2 questions per thread.

Let's begin with the first one:

$\displaystyle \frac{w^{\frac{1}{2}}\cdot w^{\frac{3}{2}}}{w}=w^{\frac{1}{2}}\cdot w^{\frac{3}{2}}\cdot w^{-1}$

Now, add the exponents...what do you get?
Are you suggesting that i should make 3 threads?
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September 9th, 2014, 09:39 AM   #6
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Originally Posted by ONEnONLY View Post


3) Simplify (2 - v3)(2+v3)
$\displaystyle We\ have \ a\ mathematical\ relationship:
\\\;\\
(a-b)(a+b)=a^2-b^2
\\\;\\
So
\\\;\\
(2-\sqrt3)(2+\sqrt3)=2^2-(\sqrt3)^2= ...$
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September 9th, 2014, 09:45 AM   #7
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It is almost impossible to "teach" from here...
You are almost asking the same as teaching you
how to ride a bicycle in one day, when you
don't know what handlebars and pedals are...
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September 9th, 2014, 09:50 AM   #8
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Originally Posted by Denis View Post
It is almost impossible to "teach" from here...
You are almost asking the same as teaching you
how to ride a bicycle in one day, when you
don't know what handlebars and pedals are...
The thing is, teaching what handlebars and pedals are is really easy, and also learning it is really easy too. I really just want the answers, i will learn in lessons. I need this just so i can give it back to the teacher and he can tick the 'done' box...
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September 9th, 2014, 10:17 AM   #9
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Originally Posted by ONEnONLY View Post
I really just want the answers, i will learn in lessons. I need this just so i can give it back to the teacher and he can tick the 'done' box...
I thought everybody from the UK was honest!!

Well, I'm sure not contributing to a "counterfeit pass".
Good luck.
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September 9th, 2014, 10:23 AM   #10
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I thought everybody from the UK was honest!!

Well, I'm sure not contributing to a "counterfeit pass".
Good luck.
I hate you. I bet you have no life.
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