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September 8th, 2014, 05:53 AM  #1 
Newbie Joined: Sep 2014 From: city Posts: 9 Thanks: 1  Solve the system of equations
\[\left\{ \begin{array}{l} 3{x^2}  2x + 5 + 2x\sqrt {{x^2} + 1} = 2y\sqrt {{{\left( {y + 1} \right)}^2} + 1} \\ {x^2} + 2{y^2} + 2x = 4y + 3 \end{array} \right.\] 
September 8th, 2014, 09:42 AM  #2 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,947 Thanks: 987 
Yikes! Soroban is very good at this kind, and will be along soon to help you... 

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