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August 26th, 2014, 06:20 AM  #1 
Senior Member Joined: Nov 2013 Posts: 434 Thanks: 8  Given conditions, prove the following 
August 26th, 2014, 07:16 AM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 520 Math Focus: Calculus/ODEs 
Please take more care in giving your threads titles. You post problem after problem with no effort ever shown, the least you can do is give your threads descriptive titles.

August 26th, 2014, 01:00 PM  #3 
Global Moderator Joined: May 2007 Posts: 6,727 Thanks: 687  
August 26th, 2014, 01:23 PM  #4  
Global Moderator Joined: Dec 2006 Posts: 20,464 Thanks: 2038 
That's incorrect, as x = y = z = 0 isn't the only possibility. Quote:
y² = y(a(bx + ay) + cx) = abxy + a²y² + cxy. By subtraction, x²(1  b²) = y²(1  a²). Similarly, y²(1  c²) = z²(1  b²). If a², b² and c² all differ from 1, the required result follows. Last edited by skipjack; August 26th, 2014 at 02:46 PM.  

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