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November 13th, 2008, 06:24 PM   #1
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Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?

How Would you solve this problem?

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November 14th, 2008, 01:41 AM   #2
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Re: Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?

I think if we want to get the value of x,
Both of statement together are sufficient,but neither ALONE is sufficient.
x is certain by QS and SU , QS is certain by RQ and RS ; SU is certain by ST and UT.
only can we get a static value of x by making sure relationship between QS and SU , ST and UT .
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November 14th, 2008, 04:33 AM   #3
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I've seen this easy problem before. Where does it come from?

Obviously, x is not "certain by QS and SU".
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November 14th, 2008, 12:23 PM   #4
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Re: Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?

Equal angles at Q and S are "m". Equal angles at S and U are "n". Pi [radians] = straight line or angle sum of triangle.

R = Pi - 2m T = Pi - 2n
R + T = 2Pi - 2(m+n)) = Pi/2 [from large triangle]
m + n = 3Pi/4
x = Pi/4
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November 14th, 2008, 12:28 PM   #5
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Re: Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?

Can't seen to edit; a common problem with these sites and cookie enablement. Anyhow, the third statement is fact. Both statements are necessary and sufficient.
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