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November 13th, 2008, 06:24 PM  #1 
Newbie Joined: Nov 2008 Posts: 1 Thanks: 0  Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE? 
November 14th, 2008, 01:41 AM  #2 
Newbie Joined: Nov 2008 Posts: 3 Thanks: 0  Re: Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?
I think if we want to get the value of x, Both of statement together are sufficient,but neither ALONE is sufficient. x is certain by QS and SU , QS is certain by RQ and RS ; SU is certain by ST and UT. only can we get a static value of x by making sure relationship between QS and SU , ST and UT . 
November 14th, 2008, 04:33 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,969 Thanks: 2222 
I've seen this easy problem before. Where does it come from? Obviously, x is not "certain by QS and SU". 
November 14th, 2008, 12:23 PM  #4 
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?
Equal angles at Q and S are "m". Equal angles at S and U are "n". Pi [radians] = straight line or angle sum of triangle. R = Pi  2m T = Pi  2n R + T = 2Pi  2(m+n)) = Pi/2 [from large triangle] m + n = 3Pi/4 x = Pi/4 
November 14th, 2008, 12:28 PM  #5 
Senior Member Joined: Mar 2007 Posts: 428 Thanks: 0  Re: Trinagle Problem. Math Award Winner Can't Solve, IMPOSSIBLE?
Can't seen to edit; a common problem with these sites and cookie enablement. Anyhow, the third statement is fact. Both statements are necessary and sufficient.


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