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November 10th, 2008, 11:28 PM  #1 
Newbie Joined: Nov 2008 Posts: 1 Thanks: 0  Circle segment?
I need to do some programming at work. Can this problem be solved? Thanks in advance. Chris 
November 11th, 2008, 08:12 AM  #2 
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: Circle segment?
AD=3.99 so CD = 3.99/2 Center "O": OE = 4.146, CE = .51145, so OC = 4.146  .51145 OD = 4.146 You might want to first check for consistency, using Pythagoras on triangle OCD. 
November 11th, 2008, 10:00 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 20,804 Thanks: 2150 
Dave mistyped the value of CE; the values are consistent. I'll use "O" for the central point and assume certain angles are right angles. By Pythagoras's theorem, (x + OC)^2 + BC^2 = r^2 and OC^2 + CD^2 = r^2, so x = sqrt(r^2  BC^2)  sqrt(r^2  CD^2). 
November 11th, 2008, 11:33 AM  #4 
Senior Member Joined: Jul 2008 Posts: 895 Thanks: 0  Re: Circle segment?
Oops.

November 17th, 2008, 09:28 AM  #5 
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,949 Thanks: 1141 Math Focus: Elementary mathematics and beyond  Re: Circle segment?
x = r(cos(sin^1(BC/r)))r+CE


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