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November 10th, 2008, 11:28 PM   #1
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Circle segment?

I need to do some programming at work. Can this problem be solved? Thanks in advance.

Chris

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November 11th, 2008, 08:12 AM   #2
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Re: Circle segment?

AD=3.99 so CD = 3.99/2
Center "O": OE = 4.146, CE = .51145, so OC = 4.146 - .51145
OD = 4.146

You might want to first check for consistency, using Pythagoras on triangle OCD.
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November 11th, 2008, 10:00 AM   #3
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Dave mistyped the value of CE; the values are consistent.

I'll use "O" for the central point and assume certain angles are right angles.
By Pythagoras's theorem, (x + OC)^2 + BC^2 = r^2 and OC^2 + CD^2 = r^2,
so x = sqrt(r^2 - BC^2) - sqrt(r^2 - CD^2).
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November 11th, 2008, 11:33 AM   #4
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Re: Circle segment?

Oops.
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November 17th, 2008, 09:28 AM   #5
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Re: Circle segment?

x = r(cos(sin^-1(BC/r)))-r+CE
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