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 June 26th, 2014, 11:28 PM #1 Member   Joined: Jun 2014 From: Brighton Posts: 49 Thanks: 2 Required help to solve algebra 1 homework Vinay's age after six years will be three-sevenths of his father's age. Ten years ago, the ratio of their ages was 1:5. What is Vinay's father's age at present? Last edited by skipjack; June 27th, 2014 at 07:33 PM. June 27th, 2014, 01:29 AM #2 Newbie   Joined: Jun 2014 From: India Posts: 2 Thanks: 0 Solution to Age problem Let Vinay’s age before 10 years be x. So his father’s age before 10 years will be 5x. After 6 years Vinay’s age will be x+10+6 = x+16 and father’s will be 5x +16. As per the given condition; x+16=3/7*(5x+16) 7(x+16)=3(5x+16) 7x+112=15x+48 64=8x X=8 Father’s present age is 5x+10=5*8+10=40+10 = 50 years June 27th, 2014, 08:04 AM   #3
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Hello, burgess!

Another approach . . .

Quote:
 Vinay's age after six years will be three-seventh of his father's age. Ten years ago the ratio of their ages was 1:5. What is Vinay's father's age at present?

Let $V$ = Vinday's present age.
Let $F$ = his father's present age.

"After 6 years, Vinay's age will be 3/7 of his father's age."

In 6 years, they will both be 6 years older.
Vinay will be $V+6$; his father will be $F+6.$

At that time: $\:V+6 \:=\:\frac{3}{7}(F+6) \quad\Rightarrow\quad 7V - 3F \:=\:-24\;\;$

"Ten years ago, the ratio of their ages was 1:5."

Ten years ago, they were both 10 years younger.
Vinay was $V-10$; his father was $F=10.$

At that time: $\:\dfrac{V-10}{F-10} \:=\:\dfrac{1}{5} \quad\Rightarrow\quad 5V - F \:=\:40\;\;$

Solve the system of equations: $\:V = 18,\;F = 50.$ Tags algebra, homework, required, solve Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post burgess Complex Analysis 1 June 23rd, 2014 11:15 AM djbeatsent Algebra 3 December 11th, 2013 07:33 AM Tutu Trigonometry 7 July 3rd, 2012 09:16 PM hatchelhoff Algebra 4 November 4th, 2011 06:08 PM ramy09 Complex Analysis 1 November 29th, 2009 04:50 PM

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