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July 15th, 2014, 12:53 PM  #11 
Member Joined: Jun 2014 From: pennsylvania Posts: 45 Thanks: 0 
Just want to bump this topic, It was never finished being explained.

July 15th, 2014, 06:19 PM  #12  
Global Moderator Joined: Dec 2006 Posts: 16,773 Thanks: 1234 
$\displaystyle 90 \le \frac{84 + 94 + 91 + h}{4} \le 95 \\ 90 \le \dfrac{269 + h}{4} \le 95 \\ 360 \le 269 + h \le 380 \\ 91 \le h \le 111$ $\displaystyle C = \frac{400 + 15n}{n} = \frac{400}{n} + 15 = 17$ when $n$ = 200. No. Quote:
To calculate the volume to subtract, use r = (21.504/2)mm = 10.752mm and h = 37mm in the formula V = πr²h/3. The volume you subtract it from is calculated by using the same formula with r = 34mm and h = 117mm. Can you now do these calculations and post your working? Last edited by skipjack; July 15th, 2014 at 07:11 PM.  
April 16th, 2017, 07:20 PM  #13 
Newbie Joined: May 2012 Posts: 5 Thanks: 0 
For the Lab tech question it's The volume of a cone = Where R is the radius of the base and H is the height of the cone. R=34 H = 117. V = 34 x 34 x 117 = about 117,000. Since the cone is only 80% filled, the actual volume is about 100,00 which is option B. 

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