My Math Forum GED assistance #2

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 July 15th, 2014, 12:53 PM #11 Member   Joined: Jun 2014 From: pennsylvania Posts: 45 Thanks: 0 Just want to bump this topic, It was never finished being explained.
July 15th, 2014, 06:19 PM   #12
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$\displaystyle 90 \le \frac{84 + 94 + 91 + h}{4} \le 95 \\ 90 \le \dfrac{269 + h}{4} \le 95 \\ 360 \le 269 + h \le 380 \\ 91 \le h \le 111$

$\displaystyle C = \frac{400 + 15n}{n} = \frac{400}{n} + 15 = 17$ when $n$ = 200.

Quote:
 Originally Posted by SMARTYPANTS . . . don't you mean the top part is a cylinder not a cone?
No.

Quote:
 Originally Posted by SMARTYPANTS Does the dotted line represent where the 80mm mark is from the top 37mm?
No.

To calculate the volume to subtract, use r = (21.504/2)mm = 10.752mm and h = 37mm in the formula V = πr²h/3. The volume you subtract it from is calculated by using the same formula with r = 34mm and h = 117mm. Can you now do these calculations and post your working?

Last edited by skipjack; July 15th, 2014 at 07:11 PM.

 April 16th, 2017, 07:20 PM #13 Newbie   Joined: May 2012 Posts: 5 Thanks: 0 For the Lab tech question it's The volume of a cone = Where R is the radius of the base and H is the height of the cone. R=34 H = 117. V = 34 x 34 x 117 = about 117,000. Since the cone is only 80% filled, the actual volume is about 100,00 which is option B.

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volume of cone 117 mm 68mm

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