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July 15th, 2014, 01:53 PM   #11
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Just want to bump this topic, It was never finished being explained.
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July 15th, 2014, 07:19 PM   #12
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$\displaystyle 90 \le \frac{84 + 94 + 91 + h}{4} \le 95 \\
90 \le \dfrac{269 + h}{4} \le 95 \\
360 \le 269 + h \le 380 \\
91 \le h \le 111$

$\displaystyle C = \frac{400 + 15n}{n} = \frac{400}{n} + 15 = 17$ when $n$ = 200.

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. . . don't you mean the top part is a cylinder not a cone?
No.

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Does the dotted line represent where the 80mm mark is from the top 37mm?
No.

To calculate the volume to subtract, use r = (21.504/2)mm = 10.752mm and h = 37mm in the formula V = πr²h/3. The volume you subtract it from is calculated by using the same formula with r = 34mm and h = 117mm. Can you now do these calculations and post your working?

Last edited by skipjack; July 15th, 2014 at 08:11 PM.
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April 16th, 2017, 08:20 PM   #13
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For the Lab tech question it's

The volume of a cone =

Where R is the radius of the base and H is the height of the cone.

R=34 H = 117. V = 34 x 34 x 117 = about 117,000. Since the cone is only 80% filled, the actual volume is about 100,00 which is option B.
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