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June 13th, 2014, 06:23 AM   #1
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a^1/3-b^1/3

How is it that a^1/3-b^1/3 can be written as (a-b)/(a^2/3-(ab)^1/3+b^2/3)?

:I don't remember whether it's -b^2/3 or +b^2/3.


Anyways, how do you write a^1/3-b^1/3 in (a-b)/x form?

Please help
as soon as possible. Running out of time. My exam begins in 32 hours.

Last edited by skipjack; June 13th, 2014 at 11:35 PM.
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June 13th, 2014, 08:15 AM   #2
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$\displaystyle \left(a^{\frac{1}{3}} - b^{\frac{1}{3}}\right)\left(a^{\frac{2}{3}} + (ab) ^{\frac{1}{3}} + b^{\frac{2}{3}}\right) = a-b$
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June 13th, 2014, 03:49 PM   #3
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It is easier to see as:

$\displaystyle (x-y)(x^2+xy+y^2)=x^3-y^3$
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June 13th, 2014, 09:31 PM   #4
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thank you so much yall
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