My Math Forum a^1/3-b^1/3

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 June 13th, 2014, 06:23 AM #1 Newbie   Joined: Jun 2014 From: chennai Posts: 17 Thanks: 0 a^1/3-b^1/3 How is it that a^1/3-b^1/3 can be written as (a-b)/(a^2/3-(ab)^1/3+b^2/3)? :I don't remember whether it's -b^2/3 or +b^2/3. Anyways, how do you write a^1/3-b^1/3 in (a-b)/x form? Please help as soon as possible. Running out of time. My exam begins in 32 hours. Last edited by skipjack; June 13th, 2014 at 11:35 PM.
 June 13th, 2014, 08:15 AM #2 Math Team   Joined: Apr 2010 Posts: 2,780 Thanks: 361 $\displaystyle \left(a^{\frac{1}{3}} - b^{\frac{1}{3}}\right)\left(a^{\frac{2}{3}} + (ab) ^{\frac{1}{3}} + b^{\frac{2}{3}}\right) = a-b$ Thanks from harryjobs
 June 13th, 2014, 03:49 PM #3 Global Moderator   Joined: May 2007 Posts: 6,854 Thanks: 744 It is easier to see as: $\displaystyle (x-y)(x^2+xy+y^2)=x^3-y^3$ Thanks from harryjobs
 June 13th, 2014, 09:31 PM #4 Newbie   Joined: Jun 2014 From: chennai Posts: 17 Thanks: 0 thank you so much yall

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