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 November 4th, 2008, 08:27 PM #1 Newbie   Joined: Oct 2008 Posts: 6 Thanks: 0 urgent If X is normally distributed with mean 40 and standard deviation of 0.8 , find the value of a such that (1) P ( | X-40 | < a ) = 0.7521 (2) P ( | X-40 ) > a ) = 0.2812
November 5th, 2008, 12:30 PM   #2
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Re: urgent

Quote:
 Originally Posted by gladtoknow If X is normally distributed with mean 40 and standard deviation of 0.8 , find the value of a such that (1) P ( | X-40 | < a ) = 0.7521 (2) P ( | X-40 ) > a ) = 0.2812
Let Y=(X-40)/0.8. Y is normally distributed with mean 0 and std. dev. 1, which is available in tables.

Your problems are then find a for P(|Y|<0.8a)=0.7521 and find a for P(|Y|>0.8a)=0.2812.

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