November 4th, 2008, 08:27 PM  #1 
Newbie Joined: Oct 2008 Posts: 6 Thanks: 0  urgent
If X is normally distributed with mean 40 and standard deviation of 0.8 , find the value of a such that (1) P (  X40  < a ) = 0.7521 (2) P (  X40 ) > a ) = 0.2812 
November 5th, 2008, 12:30 PM  #2  
Global Moderator Joined: May 2007 Posts: 6,307 Thanks: 526  Re: urgent Quote:
Your problems are then find a for P(Y<0.8a)=0.7521 and find a for P(Y>0.8a)=0.2812.  

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