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June 2nd, 2014, 12:27 PM   #1
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simplifying with fractions

Hi

Another very basic problem...

How do you treat the x when multiplying it by a fraction? (in order to remove the brackets?)

y-4 = 1/2(x+2)


Thanks in advance.

Mark

Last edited by skipjack; June 4th, 2014 at 03:11 AM.
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June 2nd, 2014, 01:02 PM   #2
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Multiplying both sides by 2 gives 2y - 8 = x + 2.
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June 2nd, 2014, 03:19 PM   #3
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$\displaystyle y-4=\frac { \left( x+2 \right) }{ 2 } \\ \\ 2\cdot y-2\cdot 4=\frac { \left( x+2 \right) }{ 2 } \cdot 2\\ \\ 2y-8=x+2\\ \\ x=2y-8-2\\ \\ x=2y-10=2\left( y-5 \right)$
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Last edited by perfect_world; June 2nd, 2014 at 03:24 PM.
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June 3rd, 2014, 12:22 AM   #4
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Quote:
Originally Posted by markcr View Post
How do you treat the x when multiplying it by a fraction?
1/2x = x/2, so 1/2(x + 2) = x/2 + 1.
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June 3rd, 2014, 12:36 AM   #5
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Thanks everyone!

Mark
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June 3rd, 2014, 01:07 PM   #6
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mmm...now what if it's a negative fraction:

y – 4 = -1/2 (x+2)
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June 3rd, 2014, 01:22 PM   #7
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Quote:
Originally Posted by markcr View Post
mmm...now what if it's a negative fraction:
y – 4 = -1/2 (x+2)
Just multiply by -1:
-y + 4 = 1/2(x+2)

Make it clearer:
-y + 4 = (x+2) / 2
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