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 June 2nd, 2014, 02:37 AM #1 Newbie   Joined: Jun 2014 From: home Posts: 1 Thanks: 0 simple transposition Hi I cannot work out how to transpose formula examples that have a division on one side. eg 15/x = 3 to get x on one side my first thought is to perform something regarding the 15 to give me 15/3 on the RHS. But I don't think I can really do this, and I have to follow a two step process such as divide multiply both sides by x 15 = 3*x then divide both sides by 3 I kind of see why I try to do some illogical(sadly it seems logical to me) initial calculation with the 15 to single out the x. Is it always a two step process? Thanks
 June 2nd, 2014, 07:36 AM #2 Senior Member     Joined: Nov 2013 From: Baku Posts: 502 Thanks: 56 Math Focus: Geometry $\displaystyle \frac{a}{b} = c \Rightarrow a=bc \; \& \; \frac{a}{c} = b$ $\displaystyle ab=c \Rightarrow \frac{c}{b} = a \; \& \; \frac{c}{a} = c$ It's basic arithmetic.
 June 2nd, 2014, 05:36 PM #3 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039 Remember that 15/x = 3 is "really" 15/x = 3/1 And: if a/b = c/d then a*d = b*c So: 15*1 = 3*x
June 3rd, 2014, 12:16 AM   #4
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Quote:
 Originally Posted by rightsidedbrain Is it always a two step process?
Divide each side of the equation 15/x = 3 into 15.
That gives you 15/(15/x) = 15/3, i.e. x = 5.

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