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 June 2nd, 2014, 02:37 AM #1 Newbie   Joined: Jun 2014 From: home Posts: 1 Thanks: 0 simple transposition Hi I cannot work out how to transpose formula examples that have a division on one side. eg 15/x = 3 to get x on one side my first thought is to perform something regarding the 15 to give me 15/3 on the RHS. But I don't think I can really do this, and I have to follow a two step process such as divide multiply both sides by x 15 = 3*x then divide both sides by 3 I kind of see why I try to do some illogical(sadly it seems logical to me) initial calculation with the 15 to single out the x. Is it always a two step process? Thanks June 2nd, 2014, 07:36 AM #2 Senior Member   Joined: Nov 2013 From: Baku Posts: 502 Thanks: 56 Math Focus: Geometry $\displaystyle \frac{a}{b} = c \Rightarrow a=bc \; \& \; \frac{a}{c} = b$ $\displaystyle ab=c \Rightarrow \frac{c}{b} = a \; \& \; \frac{c}{a} = c$ It's basic arithmetic. June 2nd, 2014, 05:36 PM #3 Math Team   Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1039 Remember that 15/x = 3 is "really" 15/x = 3/1 And: if a/b = c/d then a*d = b*c So: 15*1 = 3*x June 3rd, 2014, 12:16 AM   #4
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Quote:
 Originally Posted by rightsidedbrain Is it always a two step process?
Divide each side of the equation 15/x = 3 into 15.
That gives you 15/(15/x) = 15/3, i.e. x = 5. Tags simple, transposition Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post adamfoley Algebra 8 February 12th, 2015 04:40 AM Sadlercomfort Linear Algebra 5 April 28th, 2014 05:19 AM randomFire Algebra 6 February 1st, 2011 12:17 AM skylineview945r2 Algebra 5 January 9th, 2011 04:23 PM pauliewalnuts Calculus 2 May 6th, 2008 08:09 PM

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