My Math Forum  

Go Back   My Math Forum > High School Math Forum > Algebra

Algebra Pre-Algebra and Basic Algebra Math Forum


Thanks Tree4Thanks
  • 1 Post By mared
  • 2 Post By ldxylizhi
  • 1 Post By ldxylizhi
Reply
 
LinkBack Thread Tools Display Modes
May 30th, 2014, 12:04 AM   #1
Senior Member
 
Joined: Nov 2013

Posts: 434
Thanks: 8

solve

Thanks from raul21
mared is offline  
 
May 30th, 2014, 01:08 AM   #2
Senior Member
 
raul21's Avatar
 
Joined: Apr 2014
From: zagreb, croatia

Posts: 234
Thanks: 33

Math Focus: philosophy/found of math, metamath, logic, set/category/order/number theory, algebra, topology
e^ln{x^x} = e^(ln(2012^2012^2013))

x lnx = ln(2012^2012^2013) (because e^x is an injection)

x lnx = 2013 ln (2012^2012)

x lnx = 2013 mult. 2012 ln 2012

x lnx = 4050156 ln 2012


that's all i could menage for now...am i even going in the right direction?
raul21 is offline  
May 30th, 2014, 01:26 AM   #3
Newbie
 
Joined: May 2014
From: China

Posts: 4
Thanks: 4

here is my answer.
Attached Images
File Type: jpg Camera360_2014_5_30_051909_jpg.jpg (96.4 KB, 16 views)
Thanks from perfect_world and raul21
ldxylizhi is offline  
May 30th, 2014, 01:29 AM   #4
Senior Member
 
Joined: Aug 2011

Posts: 334
Thanks: 8

Wat is the interest of such computation ?

http://http://www.wolframalpha.com/i...82012%29+for+x
Attached Images
File Type: jpg LambertW.JPG (13.5 KB, 10 views)
JJacquelin is offline  
May 30th, 2014, 01:46 AM   #5
Newbie
 
Joined: May 2014
From: China

Posts: 4
Thanks: 4

i think you may ignore that as follows.

Quote:
Originally Posted by JJacquelin View Post
Wat is the interest of such computation ?

http://http://www.wolframalpha.com/i...82012%29+for+x
i think you may ignore that as follows.
Attached Images
File Type: jpg 1.jpg (19.3 KB, 2 views)
Thanks from raul21
ldxylizhi is offline  
May 30th, 2014, 01:50 AM   #6
Senior Member
 
raul21's Avatar
 
Joined: Apr 2014
From: zagreb, croatia

Posts: 234
Thanks: 33

Math Focus: philosophy/found of math, metamath, logic, set/category/order/number theory, algebra, topology
Quote:
Originally Posted by ldxylizhi View Post
here is my answer.
Congrats. i just forgot to apply ln once again.
raul21 is offline  
May 30th, 2014, 07:05 AM   #7
Senior Member
 
Joined: Jul 2013
From: United Kingdom

Posts: 471
Thanks: 40

Quote:
Originally Posted by ldxylizhi View Post
here is my answer.
The answer is right. I'll eat my words.

$\displaystyle 2012\cdot { 2012 }^{ 2012 }={ 2012 }^{ 2013 }$

See these two links:

*(2012^2012)^(2012^2012) - Wolfram|Alpha

*2012^(2012^2013) - Wolfram|Alpha

Last edited by perfect_world; May 30th, 2014 at 07:38 AM.
perfect_world is offline  
May 30th, 2014, 07:32 AM   #8
Senior Member
 
Joined: Jul 2013
From: United Kingdom

Posts: 471
Thanks: 40

actually, it's correct. lol. Got caught out by the simplicity of it. Doh!

Last edited by perfect_world; May 30th, 2014 at 07:47 AM.
perfect_world is offline  
Reply

  My Math Forum > High School Math Forum > Algebra

Tags
solve


« log | solve this »

Thread Tools
Display Modes






Copyright © 2019 My Math Forum. All rights reserved.