My Math Forum Reverse operation of exponentation

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 May 3rd, 2014, 07:09 AM #1 Senior Member     Joined: Feb 2014 From: Louisiana Posts: 156 Thanks: 6 Math Focus: algebra and the calculus Reverse operation of exponentation As far as I know, in the equation $\displaystyle b^{y}=x$, $\displaystyle log_{b}(x) = y$ is the "reverse" operation of exponentiation. However, in the equation $\displaystyle b^{y}=x$, why isn't $\displaystyle b = \sqrt[y]{x}$ the reverse operation?
 May 3rd, 2014, 08:10 AM #2 Senior Member     Joined: Apr 2014 From: Greater London, England, UK Posts: 320 Thanks: 156 Math Focus: Abstract algebra That would be the reverse operation to make $b$ (rather than $y$) the subject of the equation. Thanks from Mr Davis 97

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