Algebra Pre-Algebra and Basic Algebra Math Forum

 May 3rd, 2014, 07:09 AM #1 Senior Member   Joined: Feb 2014 From: Louisiana Posts: 156 Thanks: 6 Math Focus: algebra and the calculus Reverse operation of exponentation As far as I know, in the equation $\displaystyle b^{y}=x$, $\displaystyle log_{b}(x) = y$ is the "reverse" operation of exponentiation. However, in the equation $\displaystyle b^{y}=x$, why isn't $\displaystyle b = \sqrt[y]{x}$ the reverse operation? May 3rd, 2014, 08:10 AM #2 Senior Member   Joined: Apr 2014 From: Greater London, England, UK Posts: 320 Thanks: 156 Math Focus: Abstract algebra That would be the reverse operation to make $b$ (rather than $y$) the subject of the equation. Thanks from Mr Davis 97 Tags exponentation, operation, reverse Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post ravynware Algebra 0 April 15th, 2012 07:11 PM vdrn Number Theory 28 October 22nd, 2011 04:07 PM swtrse Number Theory 2 August 6th, 2009 04:53 AM NumberA Algebra 5 April 19th, 2009 11:03 AM Clox Algebra 2 January 23rd, 2008 12:24 AM

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