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May 3rd, 2014, 07:09 AM   #1
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Reverse operation of exponentation

As far as I know, in the equation $\displaystyle b^{y}=x$, $\displaystyle log_{b}(x) = y$ is the "reverse" operation of exponentiation. However, in the equation $\displaystyle b^{y}=x$, why isn't $\displaystyle b = \sqrt[y]{x}$ the reverse operation?
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May 3rd, 2014, 08:10 AM   #2
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That would be the reverse operation to make $b$ (rather than $y$) the subject of the equation.
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