
Algebra PreAlgebra and Basic Algebra Math Forum 
 LinkBack  Thread Tools  Display Modes 
May 3rd, 2014, 07:09 AM  #1 
Senior Member Joined: Feb 2014 From: Louisiana Posts: 156 Thanks: 6 Math Focus: algebra and the calculus  Reverse operation of exponentation
As far as I know, in the equation $\displaystyle b^{y}=x$, $\displaystyle log_{b}(x) = y$ is the "reverse" operation of exponentiation. However, in the equation $\displaystyle b^{y}=x$, why isn't $\displaystyle b = \sqrt[y]{x}$ the reverse operation?

May 3rd, 2014, 08:10 AM  #2 
Senior Member Joined: Apr 2014 From: Greater London, England, UK Posts: 320 Thanks: 156 Math Focus: Abstract algebra 
That would be the reverse operation to make $b$ (rather than $y$) the subject of the equation.


Tags 
exponentation, operation, reverse 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
reverse engineering a graph  ravynware  Algebra  0  April 15th, 2012 07:11 PM 
reverse n  vdrn  Number Theory  28  October 22nd, 2011 04:07 PM 
Reverse Modulo  swtrse  Number Theory  2  August 6th, 2009 04:53 AM 
Reverse solve f(x)?  NumberA  Algebra  5  April 19th, 2009 11:03 AM 
Reverse calculation  Clox  Algebra  2  January 23rd, 2008 12:24 AM 